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3 years ago

If the angle ZYX measures 45 degrees ,then arc XY measures 45 degrees. TRUE OR FALSE ?!

Mathematics

1 answer:

Angelina_Jolie [31]3 years ago

6 0

The picture in the attached figure

the correct question is
<span>If the angle ZYX measures 45 degrees, then arc XZ measures 45 degrees. TRUE OR FALSE ?!

we know that
if </span>angle ZYX measures 45 degrees
then
arc XZ=angle ZYX---------> by central angle

therefore
arc XZ=45°

the answer is
TRUE

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Manuel bought a balloon (that is a perfect sphere) with a radius of 2 \text{ cm}2 cm2, start text, space, c, m, end text. He wan

mote1985 [20]

Answer:

<h2>The required ratio is 8</h2>

Step-by-step explanation:

Volume of a sphere = $\frac{4}{3}\pi r^{3}$ where r is the radius of the sphere.

If manuel bought a balloon (that is a perfect sphere) with a radius of 2cm, the original volume of the sphere is expressed as;

Vo = $\frac{4}{3}\pi (2)^{3}$

$Vo = \frac{4}{3}\pi *8\\Vo = \frac{32 \pi}{3}$

If he wanted his balloon to be bigger and he blew 2 big breaths of air into the balloon, if each big breath increased the balloon's radius by 1cm, the total radius will be the initial radius of the sphere plus the new radius after expansion.

radius of current sphere = 2cm+(1cm+1cm) = 4cm

Volume of the current sphere Vc = $\frac{4}{3}\pi (4)^{3}$

$Vc = \frac{4}{3}\pi *64\\Vc = \frac{256 \pi}{3} \\$

The ratio of the current volume of the balloon Vc to the original volume of the balloon Vo will be expressed as;

Vc/Vo = $\frac{\frac{256\pi}{3} }{\frac{32\pi}{3} }$

$\frac{Vc}{Vo}=\frac{256\pi}{3}*\frac{3}{32\pi} \\\frac{Vc}{Vo}=\frac{256}{32}\\\frac{Vc}{Vo}= 8$

The required ratio is 8

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2 years ago

Multiply and simplify: sq rt 7x ((sq rt x)-7sq rt. 7)

jarptica [38.1K]

7x(√x - 7√7) Multiply √7x to "√x" and "-7√7" respectively:
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Extract the squares: x√7 - 7*7√x

Then, we simplify: x√7 - 49√x
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2 years ago

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A display case of hat pins are marked 5 for $3. If Patty has $21, how many hat pins can Patty get? (assume no other taxes and fe

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Answer: 35

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1 year ago

A triangle is formed from the points L(-3, 6), N(3, 2) and P(1, -8). Find the equation of the following lines:

Dima020 [189]

Answer:

Part A) $y=\frac{3}{4}x-\frac{1}{4}$

Part B) $y=\frac{2}{7}x-\frac{5}{7}$

Part C) $y=\frac{2}{7}x+\frac{8}{7}$

see the attached figure to better understand the problem

Step-by-step explanation:

we have

points L(-3, 6), N(3, 2) and P(1, -8)

Part A) Find the equation of the median from N

we Know that

The median passes through point N to midpoint segment LP

step 1

Find the midpoint segment LP

The formula to calculate the midpoint between two points is equal to

$M(\frac{x1+x2}{2},\frac{y1+y2}{2})$

we have

L(-3, 6) and P(1, -8)

substitute the values

$M(\frac{-3+1}{2},\frac{6-8}{2})$

$M(-1,-1)$

step 2

Find the slope of the segment NM

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

we have

N(3, 2) and M(-1,-1)

substitute the values

$m=\frac{-1-2}{-1-3}$

$m=\frac{-3}{-4}$

$m=\frac{3}{4}$

step 3

Find the equation of the line in point slope form

$y-y1=m(x-x1)$

we have

$m=\frac{3}{4}$

$point\ N(3, 2)$

substitute

$y-2=\frac{3}{4}(x-3)$

step 4

Convert to slope intercept form

Isolate the variable y

$y-2=\frac{3}{4}x-\frac{9}{4}$

$y=\frac{3}{4}x-\frac{9}{4}+2$

$y=\frac{3}{4}x-\frac{1}{4}$

Part B) Find the equation of the right bisector of LP

we Know that

The right bisector is perpendicular to LP and passes through midpoint segment LP

step 1

Find the midpoint segment LP

The formula to calculate the midpoint between two points is equal to

$M(\frac{x1+x2}{2},\frac{y1+y2}{2})$

we have

L(-3, 6) and P(1, -8)

substitute the values

$M(\frac{-3+1}{2},\frac{6-8}{2})$

$M(-1,-1)$

step 2

Find the slope of the segment LP

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

we have

L(-3, 6) and P(1, -8)

substitute the values

$m=\frac{-8-6}{1+3}$

$m=\frac{-14}{4}$

$m=-\frac{14}{4}$

$m=-\frac{7}{2}$

step 3

Find the slope of the perpendicular line to segment LP

Remember that

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes is equal to -1)

$m_1*m_2=-1$

we have

$m_1=-\frac{7}{2}$

$m_2=\frac{2}{7}$

step 4

Find the equation of the line in point slope form

$y-y1=m(x-x1)$

we have

$m=\frac{2}{7}$

$point\ M(-1,-1)$ ----> midpoint LP

substitute

$y+1=\frac{2}{7}(x+1)$

step 5

Convert to slope intercept form

Isolate the variable y

$y+1=\frac{2}{7}x+\frac{2}{7}$

$y=\frac{2}{7}x+\frac{2}{7}-1$

$y=\frac{2}{7}x-\frac{5}{7}$

Part C) Find the equation of the altitude from N

we Know that

The altitude is perpendicular to LP and passes through point N

step 1

Find the slope of the segment LP

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

we have

L(-3, 6) and P(1, -8)

substitute the values

$m=\frac{-8-6}{1+3}$

$m=\frac{-14}{4}$

$m=-\frac{14}{4}$

$m=-\frac{7}{2}$

step 2

Find the slope of the perpendicular line to segment LP

Remember that

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes is equal to -1)

$m_1*m_2=-1$

we have

$m_1=-\frac{7}{2}$

$m_2=\frac{2}{7}$

step 3

Find the equation of the line in point slope form

$y-y1=m(x-x1)$

we have

$m=\frac{2}{7}$

$point\ N(3,2)$

substitute

$y-2=\frac{2}{7}(x-3)$

step 4

Convert to slope intercept form

Isolate the variable y

$y-2=\frac{2}{7}x-\frac{6}{7}$

$y=\frac{2}{7}x-\frac{6}{7}+2$

$y=\frac{2}{7}x+\frac{8}{7}$

7 0

3 years ago