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d1i1m1o1n [39]
3 years ago
6

The sum of 7 and y is less than 18.

Mathematics
1 answer:
iogann1982 [59]3 years ago
4 0

Answer:

7 + y < 18

Step-by-step explanation:

"The sum of 7 and y" means that we're adding 7 and y. "Is less than 18" means we need to use the "less than" symbol. We can now write the equation as:

7 + y < 18

Hope this helps,

♥<em>A.W.E.</em><u><em>S.W.A.N.</em></u>♥

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Two sisters start in the same place and walk in opposite directions. The
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Answer:

10 yards

Step-by-step explanation:

6+4=10

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2 years ago
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If the value of 6 coins is $0.56, what are the coins?​
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1 quarter, 2 dimes, 2 nickels, and 1 penny.

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2 years ago
In the United States, the mean and standard deviation of adult men's heights are 70 inches (5 feet 10 inches) and 4 inches, resp
Artyom0805 [142]

Answer:

P(X>72)=P(\frac{X-\mu}{\sigma}>\frac{72-\mu}{\sigma})=P(Z>\frac{72-70}{4})=P(z>0.5)

And we can find this probability using the complement rule and the normal standard table:

P(z>0.5)=1-P(z

And the best solution would be:

c. 0.3085

Step-by-step explanation:

For this case we can convert all the values to inches in order to standardize the solution:

5ft * \frac{12 in}{1ft}= 60 in

6ft * \frac{12 in}{1ft}= 72 in

Let X the random variable that represent the heights of US mens, and for this case we know the distribution for X is given by:

X \sim N(70,4)  

Where \mu=70 and \sigma=4

We are interested on this probability

P(X>72)

We can use the z score formula given by:

z=\frac{x-\mu}{\sigma}

Using this formula we got:

P(X>72)=P(\frac{X-\mu}{\sigma}>\frac{72-\mu}{\sigma})=P(Z>\frac{72-70}{4})=P(z>0.5)

And we can find this probability using the complement rule and the normal standard table:

P(z>0.5)=1-P(z

And the best solution would be:

c. 0.3085

5 0
3 years ago
30/80=e/40 what is the answer?
masya89 [10]

Answer:

15

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
Is my answer correct
Kryger [21]
Yes it is thirty because when u do 5×2×3 the correct answer turns out to be 30 $o yes!!!!!!
4 0
3 years ago
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