Answer:
Ok so I dont have a paper on me, but to solve this, first you need to know, 1 ml is 1 cubic centimeter, okay so we need to find the volume, which is 4/3 times pie times r cubed, the answer to this equation will then bet 51 cubic centimeters which directly translate to 51 ml pushed out of the full cup
Explanation:
(w/w) % : The percentage mass or fraction of mass of the of solute present in total mass of the solution.

1) 100 g of 0.500% (w/w) NaI
Mass of solution = 100 g
Mass of solute = x
Required w/w % of solution = 0.500%


0.500 grams of solute needed to make 100 g of 0.500% (w/w) NaI.
2) 250 g of 0.500% (w/w) NaBr
Mass of solution = 250 g
Mass of solute = x
Required w/w % of solution = 0.500%


1.25 grams of solute needed to make 250 g of 0.500% (w/w) NaBr
3) 500 g of 1.25% (w/w) glucose
Mass of solution = 500 g
Mass of solute = x
Required w/w % of solution = 1.25%


6.25 grams of solute needed to make 500 g of 1.25% (w/w) (glucose)
4) 750 g of 2.00% (w/w) sulfuric acid.
Mass of solution = 750 g
Mass of solute = x
Required w/w % of solution = 2.00%


15.0 grams of solute needed to make 750 g of 2.00% (w/w) sulfuric acid.
Answer:
Molar mass: 212.996 g/mol
Explanation:
Formula: Al(NO3)3
Molar mass: 212.996 g/mol
IUPAC ID: Aluminium nitrate
Melting point: 72.8 °C
Boiling point: 135 °C
Density: 1.72 g/cm³
Soluble in: Water, Alcohol
Answer:
1. 7
2. 7
3. 16.60
Explanation:
1. 7
3x-3=18
+3 +3
3x=21
/3 /3
x=7
2. 7
4x-5=23
+5. +5
4x=28
/4. /4
x=7
3. 16.60
it reaches above the halfway point after 16, and it's one above it. So, it's 16.60