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azamat
3 years ago
12

K₂O +2Li Li₂O +2k how do you solve?

Chemistry
1 answer:
tiny-mole [99]3 years ago
8 0

Answer:

K₂O +2Li --> Li₂O +2K

Explanation:

On the left side, K has 2 atoms and O has one combines with Li having 2 atoms. When the process starts Li burns and got atoms from O.

Hence O has 2 ions and Li has 1 ion

so to complete the bond, Two Li will have 2 ions which can complete O by sharing his 2 icons. i.e. Li₂O

and Two atoms of K can exist like 2K

So the equation will be like

K₂O +2Li --> Li₂O +2K

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Please tell if my answer is right or wrong.
xxTIMURxx [149]
Change the places of 'acts against the motion of an object' and 'causes an object to change speed or direction'
5 0
4 years ago
When methane reacts with oxygen, the products are carbon dioxide (CO2) and water (H2O). How many grams of water are formed if 24
VashaNatasha [74]

Answer:

54 g

Explanation:

To solve this problem we will simply follow the Law of conservation of mass.

According to this law:

" The mass of product in the chemical reaction must be equal to the mass of reactant"

Given data:

mass of methane= 24 g

mass of oxygen= 96 g

mass of carbon dioxide= 66 g

mass of water= ?

Solution:

CH4 + 2O2 → CO2 +2H2O

24g + 96 g = 66 g + ?

120 g = 66 g + ?

120 g - 66 g = 54 g

so 54 g of waters are produce.

We can see that mass of water is equal to the sum of masses of reactant minus mass of product formed i.e mass of carbon dioxide.

4 0
4 years ago
Write a resonance form for pyrrole in which nitrogen has a formal charge of 1. Are comparable resonance forms possible for pyrid
Svetach [21]

Answer:

See explanation and image attached

Explanation:

Here attached are resonance forms of pyrrole and pyridine. The images were obtained from quora and researchgate respectively.

Now, we can see that in the resonance forms of pyrrole, the nitrogen atom in the heterocycle has a formal charge of +1. However, in the six membered pyridine hetrocycle, the nitrogen atom may have a formal charge of -1 or +1 as shown in the canonical structures attached. The structures in which nitrogen has a +1 formal charge in pyridine are comparable to structures obtained from pyrrole. These structures have less contribution to the structure of pyridine.

3 0
3 years ago
What volume of 0.200 M ethanol solution contains each of the following amounts?
Papessa [141]

Answer:

A. 2.3 L

B. 6.10 L

C. 0.060 L

Explanation:

The question asks the volume of a 0.200 M solution of ethanol that contains certain number of moles of ethanol.

The M in the 0.200 M stands for Molarity. This is a unit of concentration that can be expressed as:

Molarity = moles of solute / Liters of solution

In this case:

0.200 M = moles of ethanol / Liters of solution

So from the formula we can get that we can calculate the volume of the solution, as Liters of solution, given the moles in each case as:

Liters of solution = moles of ethanol / 0.200 moles/L

_______________________________________________

A. <u>0.45 mol ethanol</u>

Liters of solution = 0.45 moles / 0.200 moles/L = 2.25 L = 2.3 L

B. <u>1.22 mol ethanol</u>

Liters of solution = 1.22 moles / 0.200 moles/L = 6.10 L

C.<u> </u><u>1.2 x 10⁻² mol ethanol</u>

Liters of solution = 1.2 x 10⁻² moles / 0.200 moles/L = 0.060 L

_______________________________________________

Note: Each answer is given with the correct number of significant figures which results from the least number of significant figures in the given used values in each calculation.

7 0
3 years ago
What radionuclides is used in diagnosis of atherosclerosis
aliina [53]
Answer: technetium-99.

Explanation:

This is not an answer that you can look for in a book.

You need to do some research.

You can fiind the abstract of the article titled <span>Molecular imaging of atherosclerosis using a technetium-99m-labeled endothelin derivative.</span>

The conclusion of this scientific article is that labeling with the radiosotope Tc - 99 iis feasibele to visualize the effects of an experiment inducing atherosclerosis, which gives the answer to the question posted.
.

8 0
4 years ago
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