Let's balance step by step. We'll start with Iron (Fe)
Fe2O3 + HCl --> FeCl3 + H2O
We have 2 Fe on the left, and only one on the right, so we'll double the Fe on the right
Fe2O3 + HCl --> 2FeCl3 + H2O
Now we have six Cl on the right, and only one on the left, so we'll multiply the Cl by six on the left
Fe2O3 + 6HCl --> 2FeCl3 + H2O
Finally, we can balance the water, as we have 6 H and 3 O on the left, and 2 H and one O on the right, so we can triple the H2O on the right
Fe2O3 + 6HCl --> 2FeCl3 + 3H2O
The equation has been balanced.
They are about 4.5 billion years old. Hope this helps.
Answer:
B. water displacement is used "graduated cylinder is filled with water (100 mL) and the object is then put inside. ... If the new water level is (120 mL) we now know that the object has a volume of 20 mL."
Explanation:
Answer:
-0.1767°C (Option A)
Explanation:
Let's apply the colligative property of freezing point depression.
ΔT = Kf . m. i
i = Van't Hoff factot (number of ions dissolved). Glucose is non electrolytic so i = 1
m = molality (mol of solute / 1kg of solvent)
We have this data → 0.095 m
Kf is the freezing-point-depression constantm 1.86 °C/m, for water
ΔT = T° frezzing pure solvent - T° freezing solution
(0° - T° freezing solution) = 1.86 °C/m . 0.095 m . 1
T° freezing solution = - 1.86 °C/m . 0.095 m . 1 → -0.1767°C
