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3 years ago

Is 1/8 and 8/8 are equal parts??

Mathematics

2 answers:

exis [7]3 years ago

6 0

No. 1/8 and 8/8 are not equal. It's simple: 1 out of 8 parts is not equal to 8 out of 8 parts.

Fed [463]3 years ago

5 0

Well 1/8 is smaller than 8/8 so they should not be equal

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What is wrong with this solution?

Naily [24]

Answer:

They changed 5m into a positive when it should've stayed as a negative until you isolate the variable m at the end, making m actually equal -7.

Step-by-step explanation:

-5m - 16 = 19

-5m = 19 + 16

-5m = 35

m = 35/-5

m = -7

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3 years ago

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Is two over five irrational numbers

9966 [12]

Answer:

No, It is not irrational number.

Step-by-step explanation:

2/5 is a rational number. A rational number is a number of the form q/q where p and q are integers and q is not equal to 0.

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3 years ago

Does translation change a shapes orientation

lara [203]

Answer:

Step-by-step explanation:

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3 years ago

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F(x)=x^2 what is g(x)

AysviL [449]

Is C g(x) = -X^2 -3

This is the answer

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3 years ago

A ball of radius 15 has a round hole of radius 5 drilled through its center. Find the volume of the resulting solid. Hint: The u

OverLord2011 [107]

Answer:

The volume of the ball with the drilled hole is:

$\displaystyle\frac{8000\pi\sqrt{2}}{3}$

Step-by-step explanation:

See attached a sketch of the region that is revolved about the y-axis to produce the upper half of the ball. Notice the function y is the equation of a circle centered at the origin with radius 15:

$x^2+y^2=15^2\to y=\sqrt{225-x^2}$

Then we set the integral for the volume by using shell method:

$\displaystyle\int_5^{15}2\pi x\sqrt{225-x^2}dx$

That can be solved by substitution:

$u=225-x^2\to du=-2xdx$

The limits of integration also change:

For x=5: $u=225-5^2=200$

For x=15: $u=225-15^2=0$

So the integral becomes:

$\displaystyle -\int_{200}^{0}\pi \sqrt{u}du$

If we flip the limits we also get rid of the minus in front, and writing the root as an exponent we get:

$\displaystyle \int_{0}^{200}\pi u^{1/2}du$

Then applying the basic rule we get:

$\displaystyle\frac{2\pi}{3}u^{3/2}\Bigg|_0^{200}=\frac{2\pi(200\sqrt{200})}{3}=\frac{400\pi(10)\sqrt{2}}{3}=\frac{4000\pi\sqrt{2}}{3}$

Since that is just half of the solid, we multiply by 2 to get the complete volume:

$\displaystyle\frac{2\cdot4000\pi\sqrt{2}}{3}$

$=\displaystyle\frac{8000\pi\sqrt{2}}{3}$

5 0

3 years ago