Answer:
Rate in relationship A = (6 - 3)/(8 - 4) = 3/4 = 0.75
For Table A: Rate = (3 - 1.2)/(5 - 2) = 1.8/3 = 0.6
For table B: Rate = (3.5 - 1.4)/(5 - 2) = 2.1/3 = 0.7
For table C: Rate = (4 - 1.6)/(5 - 2) = 2.4/3 = 0.8
For table D: Rate = (2 - 1.5)/(4 - 3) = 0.5/1 = 0.5
Therefore, the correct answer is option C.
Simple..
there is a major difference between 6z and

6z means: 6 times z
and

means: z to the power of 6(z*z*z*z*z*z)
An example...
make z=2...plug n chug..
6z----> 6(2)=12
and

--->

=64
As you can see..there is a
major difference.
Thus, your answer.
The equation for simple interest is sated as follows:
A=P(1+rt), where A= The accrued amount, P=Principal invested, r=interest rate per year, and t=time in years.
For the amount invested to be atleast double the amount invested (like the current scenario), the inequality would be would be
A≥ P(1+rt) ---- 200≥100 (1+0.05t) ---- 2≥1+0.05t --- t≥(2-1)/0.05 --- t≥20 years
Therefore, for the amount to atleast double, $100 should be invested for atleast 20 years.