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kati45 [8]
2 years ago
11

What 2 numbers multiply to 80 and add to -24​

Mathematics
1 answer:
raketka [301]2 years ago
6 0

Answer:

80/2=40-24=16

Step-by-step explanation:

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Find the amount of time in years. <br><br><br><br> I=$100, P=$200, r=10%
lara31 [8.8K]

Answer:

How many years????????

4 0
3 years ago
8xy= 2(2x + y) solve for y
STatiana [176]

Answer:  \displaystyle y= \frac{2\text{x}}{4\text{x} - 1}

============================================

Work Shown:

8\text{x}y= 2(2\text{x} + y)\\\\8\text{x}y= 4\text{x} + 2y\\\\8\text{x}y - 2y= 4\text{x}\\\\y(8\text{x} - 2)= 4\text{x}\\\\y= \frac{4\text{x}}{8\text{x} - 2}\\\\y= \frac{2*2\text{x}}{2(4\text{x} - 1)}\\\\y= \frac{2\text{x}}{4\text{x} - 1}\\\\

---------------

Explanation:

The idea is to first get all the y terms to one side. I did this by subtracting 2y from both sides in the third step.

Then factor out y and divide both sides by (8x-2)

Afterward there's the optional steps of simplifying (as shown in the final two steps).

5 0
2 years ago
I posted 3 times already please help me. <br> At least try it.<br> 15 points <br> Photo above
natulia [17]

Answer:

The answer is, "The image will be in Quadrant II"

Step-by-step explanation:

When is comes to rotating something 180, whether it's clock-wise or counter clock-wise it will end in the opposite place.

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3 years ago
Read 2 more answers
Four times a number decreased by 13 minus 2 times the same number is 9. What is the number?
Flura [38]

Answer:

The number is 59

Step-by-step explanation:

13×4-2+9=59

6 0
3 years ago
Encuentra la ecuacion de la parabola con vertice en el origen y foco en las cordenadas 0,1en su forma ordinaria y general
marusya05 [52]

Answer:

x^{2}=4y

y=\frac{1}{4}x^{2}

Step-by-step explanation:

Forma ordinaria

La ecuación de la parabola de manera ordinaria está dada por:

(x-h)^{2}=4p(y-k) (1)  

Donde:

  • (h,k) es la coordenda del vértice, en nuestro caso (0,0) ya que está en el origen.
  • (h,k+p) es la coordenda del foco, en nuestro caso (0,1).

Por lo tanto h = 0, k = 0 y p = 1.

Remplazando estos valores en la ecuación de la parábola, tenemos:

(x-0)^{2}=4*1(y-0)

x^{2}=4y (2)

 

Forma general  

La forma general de una parábola esta dada por la siquiente ecuación

y=ax^{2}+bx+c

Reordenando la ecuación (2) tenemos:

y=\frac{1}{4}x^{2}

Espero esto te haya ayudado!

5 0
3 years ago
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