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pickupchik [31]
3 years ago
10

The mystery number is a four-digit number. Its digits are 5, 4, 7, and 3. The 5 and the 7 are the two middle digits.The 5 comes

after the 7.The 3 is not the first digit.What is the mystery number?
Mathematics
2 answers:
Flura [38]3 years ago
7 0
4753 seems to me like the right one
inessss [21]3 years ago
7 0

Answer: 4753

Step-by-step explanation:

Given: The mystery number is a four-digit number.

The digits used to make the number : 5, 4, 7, and 3.

Since , 5 and the 7 are the two middle digits.

Then , the number would look like -57-\ or\ -75-

The 5 comes after the 7.

Then , the number would look like -75-  [i.e.  -57- is not representing  the mystery number]

The 3 is not the first digit, then 4 must be the first digit.

Hence, the mystery number should be : 4753

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Answer:

We conclude that the machine is under filling the bags.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 436.0 gram

Sample mean, \bar{x} = 429.0 grams

Sample size, n = 40

Alpha, α = 0.05

Population standard deviation, σ = 23.0 grams

First, we design the null and the alternate hypothesis

H_{0}: \mu = 436.0\text{ grams}\\H_A: \mu < 436.0\text{ grams}

We use one-tailed(left) z test to perform this hypothesis.

Formula:

z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }

Putting all the values, we have

z_{stat} = \displaystyle\frac{429 - 436}{\frac{23}{\sqrt{40}} } = -1.92

Now, z_{critical} \text{ at 0.05 level of significance } = -1.64

Since,  

z_{stat} < z_{critical}

We reject the null hypothesis and accept the alternate hypothesis. Thus, we conclude that the machine is under filling the bags.

8 0
3 years ago
Doug estimates that his soccer team will win 7 games this year. The team actually wins 10 games. What is the percent error of Do
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Step-by-step explanation:

Percent error = \dfrac{|\text{Estimated value - Actual value}|}{\text{Actual value}}\times100\%

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Now ,   the percent error of Doug’s estimate = \dfrac{|7-10|}{10}\times100\%= \dfrac{3}{1}\times10\%=30\%

Hence, the percent error of Doug’s estimate = 30%

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