Four friends each bought a movie ticket and two boxes of candy at a movie theater. The tickets were $ 7.50 and the boxes of cand

Question

katovenus [111]

3 years ago

13

Four friends each bought a movie ticket and two boxes of candy at a movie theater. The tickets were $ 7.50 and the boxes of cand

y cost the same amount. If the total cost for all four friends was $ 58.00, what was the price of one (1) box of candy.

Mathematics

2 answers:

horsena [70] · Answer 1 · 2022-09-12T19:53:40+03:00

horsena [70]3 years ago

7 0

Answer:

$7

Step-by-step explanation:

58-7.50x4=30 58-30=28/4=7

Angelina_Jolie [31] · Answer 2 · 2022-09-12T17:43:16+03:00

Angelina_Jolie [31]3 years ago

4 0

Subtract the cost of tickets from the total. 4x7.5=30. 58-30=28. Eight boxes of candy were purchased in total. Use c to represent candy. 8c=28. Finally, divide both by 8. 28/8= 3.5. The answer is $3.50.