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katovenus [111]
3 years ago
13

Four friends each bought a movie ticket and two boxes of candy at a movie theater. The tickets were $ 7.50 and the boxes of cand

y cost the same amount. If the total cost for all four friends was $ 58.00, what was the price of one (1) box of candy.
Mathematics
2 answers:
horsena [70]3 years ago
7 0

Answer:

$7

Step-by-step explanation:

58-7.50x4=30 58-30=28/4=7

Angelina_Jolie [31]3 years ago
4 0
Subtract the cost of tickets from the total. 4x7.5=30. 58-30=28. Eight boxes of candy were purchased in total. Use c to represent candy. 8c=28. Finally, divide both by 8. 28/8= 3.5. The answer is $3.50.
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Shtirlitz [24]

The midpoint between -4 and 8 is answer B) 2

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3 years ago
What is 2 2/3 x 15 plz help for my hw
SIZIF [17.4K]
The answer is 40.You should change the 2 2/3 to improper fraction and the times it with 15.
3 0
3 years ago
Read 2 more answers
Mathematics challenge
kari74 [83]

Get the equation of the line containing PQ using the point-slope formula:

<em>y</em> - (-2) = 3/2 (<em>x</em> - (-6))

Solve for <em>y</em> to get it in slope-intercept form:

<em>y</em> = 3/2 <em>x</em> + 7

so the <em>y</em>-intercept is (0, 7).

The line containing QR is then

<em>y</em> - 7 = -3/4 (<em>x</em> - 0)

or

<em>y</em> = -3/4 <em>x</em> + 7

The point R is on the <em>x</em>-axis, so its <em>y</em>-coordinate is 0. Plug in <em>y</em> = 0 and solve for <em>x</em> to get the other coordinate:

0 = -3/4 <em>x</em> + 7

3/4 <em>x</em> = 7

<em>x</em> = 4/3×7 = 28/3

So the point R has coordinates (28/3, 0).

6 0
3 years ago
Find the distance between the points (5,0) and (-5,3)
oksano4ka [1.4K]

Answer:

10.4

Step-by-step explanation:

√(5--5)²+(0-3)²

√100+9

√109=10.4

4 0
2 years ago
As part of his retirement strategy, John plans to invest $210,000 in two different funds. He projects that the moderately high r
Maslowich

Answer:

Therefore he invested $60,000 at 9% per year and $(210,000-60,000)=$150,000 at 4% per year.

Step-by-step explanation:

Given John plans to invest $210,000 in two different funds. He projects that the moderately high risk investments should return, overtime 9% per year,while low risk investments should return about 4% per year.

He wants a supplemental income of$11,400 a year.

Let , he invested $x at 9% per year and $(210,000-x) at 4% per year.

interest=\frac{prt}{100}   p = principle , r = rate of interest and t = time

The interest earns at 9% per year= \frac{x\times 9\times 1}{100}

The interest earns at 4% per year=\frac{(210,00-x)\times 4 \times 1}{100}

According to the problem,

\frac{x\times 9\times 1}{100}+\frac{(210,00-x)\times 4 \times 1}{100}= 11400

\Leftrightarrow 9x+840000-4x=11400 \times 100

\Leftrightarrow 5x=1140000-840000

\Leftrightarrow x=\frac{300000}{5}

\Leftrightarrow x=60,000

Therefore he invested $60,000 at 9% per year and $(210,000-60,000)=$150,000 at 4% per year.

7 0
3 years ago
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