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3 years ago

Factor (5a–3b)^2–25a^2 PLS HELP 50 POINTS

Mathematics

2 answers:

Nonamiya [84]3 years ago

3 0

Answer:

(-3b) (10a -3b)

Step-by-step explanation:

(5a–3b)^2–25a^2

Replace (5a–3b) with x

x^2 - (5a) ^2

We have the difference of squares

( x-5a) (x+5a)

Now replace x with (5a -3b)

(5a -3b -5a) ( 5a -3b +5a)

Combine like terms

(-3b) (10a -3b)

KatRina [158]3 years ago

3 0

Answer:

(5a-3b)²-25a²

= 25a²+9b²-2×5a×3b-25a { (a-b)²= a²+b²-2ab}

=9b²-30ab

=3b(3b-10a)

= -3b(10a-3b)

Ans

Hope, it helped!

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Y_Kistochka [10]

Answer:

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3 years ago

An ice cream stand offers cake cones, waffle cones, or cups to hold ice cream. You can get vanilla, chocolate, strawberry, pista

Alchen [17]

Answer:

15 outcomes

Step-by-step explanation:

We have three choices of ice cream containers.

We have five choices of ice cream flavors.

We are asking for a single scoop.

Using the cake cone 5 times for each flavor, we get 5 possibilities. Repeat this with the other two container choices, and we get 3 * 5 = 15.

Hope this helped! :D

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3 years ago

In ΔKLM, m = 160 cm, ∠M=145° and ∠K=28°. Find the length of l, to the nearest 10th of a centimeter.

Montano1993 [528]

Answer:

34.0 m

Step-by-step explanation:

The total angle sum in a triangle should be 180° hence the missing angle will be given by

180°-145°-28°=7°

Using sine rule

$\frac {m}{sin M}=\frac {l}{sin L}=\frac {k}{sin K}$

By substituting 160 for m, 145° for M and 7° for L then

$\frac {160}{sin 145^{\circ}}=\frac {l}{sin 7^{\circ}}$

Making l the subject then

$l=\frac {160 sin 7^{\circ}}{sin 145^{\circ}}=33.9956345990643m\\l\approx 34.0m$

3 0

3 years ago

P-6+2<-5 solve each inequality and graph its solution, i am lost

DerKrebs [107]

Answer:

P < -1

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

$P - 6 + 2 < -5$
$P - 4 < -5$

Step 2: Add 4 to both sides.

$P - 4 + 4 < -5 + 4$
$P < -1$

Therefore, the answer is P < -1! (Also, the graphed solution is below.)

3 0

3 years ago

i need answers by tonight or the morning. its due tomarrow and im scarred to ask the teacher what to do.

kompoz [17]

I’ll explain part A and you can apply it to the other parts. The functions f(x), g(x), and m(x) are all equivalent to the given polynomials. So when it asks for f(x) + [g(x) - m(x)] you plug them in. The answer to Part A is 3x^2 +5x - z + [5x^2-3x+z - 2x^2 - 2x]. Combine the like terms (3x^2+5x^2-2x^2 = 6x^2 (because 3+5-2=6)) and so on until you’ve simplified it as much as possible!

4 0

3 years ago