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MAXImum [283]
2 years ago
10

Factor (5a–3b)^2–25a^2 PLS HELP 50 POINTS

Mathematics
2 answers:
Nonamiya [84]2 years ago
3 0

Answer:

(-3b) (10a -3b)

Step-by-step explanation:

(5a–3b)^2–25a^2

Replace (5a–3b) with x

x^2 - (5a) ^2

We have the difference of squares

( x-5a) (x+5a)

Now replace x with (5a -3b)

(5a -3b -5a) ( 5a -3b +5a)

Combine like terms

(-3b) (10a -3b)

KatRina [158]2 years ago
3 0

Answer:

(5a-3b)²-25a²

= 25a²+9b²-2×5a×3b-25a { (a-b)²= a²+b²-2ab}

=9b²-30ab

=3b(3b-10a)

= -3b(10a-3b)

Ans

Hope, it helped!

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Please help!! MathsWatch, Surd Expressions, Clip 207c
dexar [7]

Answer:

A=(72+36\sqrt{3})\ mm^2

Step-by-step explanation:

see the attached figure with letters to better understand the problem

Let

a ----> the height of rectangle in mm

b ---> the base of rectangle in mm

step 1

Find the base of rectangle

b=AB+BC+CD+DE ----> by segment addition postulate

substitute

b=3+3+3+3=12\ mm

step 2

Find the height of rectangle

a=FB+CG+GH ---> by segment addition postulate

substitute the given values

a=3+CG+3\\a=6+CG

Find the length sides CG

Applying the Pythagorean Theorem

BG^2=BC^2+CG^2

substitute the given values

6^2=3^2+CG^2

CG^2=6^2-3^2

CG=\sqrt{27}\ mm

simplify

CG=3\sqrt{3}\ mm

therefore

a=(6+3\sqrt{3})\ mm

step 3

Find the area of rectangle

A=ab

we have

a=(6+3\sqrt{3})\ mm

b=12\ mm

substitute

A=(6+3\sqrt{3})(12)=(72+36\sqrt{3})\ mm^2

8 0
3 years ago
HELP ME PLS IM DESPO
gogolik [260]
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Use trigonometry to find the missing side. Round your answer to the nearest tenth (one decimal place)
Alchen [17]

Given:

A figure of a right triangle.

To find:

The missing side by using the trigonometric ratios.

Solution:

In a right angle triangle,

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In triangle ABC,

\cos A=\dfrac{AC}{AB}

\cos (31^\circ)=\dfrac{b}{270}

0.857=\dfrac{b}{270}

Multiply both sides by 270.

0.857\times 270=b

231.39=b

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Therefore, the missing side length is b=231.4 inches.

5 0
3 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
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ch4aika [34]

Answer:

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Step-by-step explanation:

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