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2 years ago

Factor (5a–3b)^2–25a^2 PLS HELP 50 POINTS

Mathematics

2 answers:

Nonamiya [84]2 years ago

3 0

Answer:

(-3b) (10a -3b)

Step-by-step explanation:

(5a–3b)^2–25a^2

Replace (5a–3b) with x

x^2 - (5a) ^2

We have the difference of squares

( x-5a) (x+5a)

Now replace x with (5a -3b)

(5a -3b -5a) ( 5a -3b +5a)

Combine like terms

(-3b) (10a -3b)

KatRina [158]2 years ago

3 0

Answer:

(5a-3b)²-25a²

= 25a²+9b²-2×5a×3b-25a { (a-b)²= a²+b²-2ab}

=9b²-30ab

=3b(3b-10a)

= -3b(10a-3b)

Ans

Hope, it helped!

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Answer:

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Step-by-step explanation:

Given

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Required

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Substitute 6 for n

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Express 2 as 6 - 4

$(a+b)^6 = ......+15(5)^{6-4}(-\frac{1}{2})^4+.......$

By direct comparison of

$(a+b)^n = ......+ ^nC_ra^{n-r}b^r+.......$

and

$(a+b)^6 = ......+15(5)^{6-4}(-\frac{1}{2})^4+.......$

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[Solving for a]

By direct comparison of $a^{n-r} =(5)^{6-4}$

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[Solving for b]

By direct comparison of $b^r= (-\frac{1}{2})^4$

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Substitute values for a, b, n and r in

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$(5-\frac{1}{2})^6 = ......+15*(5)^{6-4}(\frac{-1}{2})^4+.......$

$(5-\frac{1}{2})^6 = ......+15(5)^{6-4}(\frac{-1}{2})^4+.......$

$(5-\frac{1}{2})^6 = ......+15(5)^2(\frac{-1}{2})^4+.......$

Check the list of options for the expression on the left hand side

The correct answer is $(5-\frac{1}{2})^6$

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