Which ordered pair (x,y) is a solution to the following?

If you get this right I will mark you as a brainliest

Thepotemich [5.8K]

The answer to this problem is A 10

8 0

3 years ago

7=3/8x-2<br> What is the answer show your work

Marina CMI [18]

Answer:

x = 24

Step-by-step explanation:

Firstly, isolate x by adding 2 to both sides.

9 = 3/8x

Then, multiply 8 to both sides.

72 = 3x

Then, divide both sides by 3.

24 = x

4 0

3 years ago

Read 2 more answers

a larger gear wheel has 40 teeth and a small gear wheel has 25 teeth. if the larger one makes 100 revolutions in a minute, how m

nevsk [136]

Lets calculate gear ration T2/T1
so the gear ratio will be 1.6 it simply means dat if u rotate large gears one full revolution it tends to turn another short wheel to 1.6 revs, so in ur qtion the large whell revs 100 den u must multiply wid 1.6*100= 160 revs

5 0

3 years ago

If two angles are complementary then both angles must be acute true or false

Oxana [17]

Answer:

If two angles are acute angles, then they are complementary. Incorrect. The converse is “If two angles are complementary, then they are acute angles” which is true and the original statement was false because two acute angles are not always complementary.

Step-by-step explanation:

7 0

3 years ago

The local oil changing business is very busy on Saturday mornings and is considering expanding. A national study of similar busi

eimsori [14]

Answer:

$t=\frac{4.2-3.6}{\frac{1.4}{\sqrt{16}}}=1.714$

Reject the null hypothesis if the observed "t" value is less than -2.131 or higher than 2.131

Rejection Zone: $t_{calculated}$ or $t_{calculated}>2.131$

In our case since our calculated value is not on the rejection zone we don't have enough evidence to reject the null hypothesis at 5% of significance.

Step-by-step explanation:

Previous concepts and data given

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=4.2$ represent the sample mean

$s=1.4$ represent the sample standard deviation

n=16 represent the sample selected

$\alpha=0.05$ significance level

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is different from 3.6, the system of hypothesis would be:

Null hypothesis: $\mu = 3.6$

Alternative hypothesis: $\mu \neq 3.6$

If we analyze the size for the sample is < 30 and we know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{4.2-3.6}{\frac{1.4}{\sqrt{16}}}=1.714$

Critical values

On this case since we have a bilateral test we need to critical values. We need to use the t distribution with $df=n-1=16-1=15$ degrees of freedom. The value for $\alpha=0.05$ and $\alpha/2=0.025$ so we need to find on the t distribution with 15 degrees of freedom two values that accumulates 0.025 of the ara on each tail. We can use the following excel codes:

"=T.INV(0.025,15)" "=T.INV(1-0.025,15)"

And we got $t_{crit}=\pm 2.131$

So the decision on this case would be:

Reject the null hypothesis if the observed "t" value is less than -2.131 or higher than 2.131

Rejection Zone: $t_{calculated}$ or $t_{calculated}>2.131$

Conclusion

In our case since our calculated value is not on the rejection zone we don't have enough evidence to reject the null hypothesis at 5% of significance.

3 0

3 years ago