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mamaluj [8]
3 years ago
5

Which equation represents a circle that contains the point (-5, 3) and has a center at (-2, 1)? Distance formula: vaa -02 (x - 1

)2 + ( + 2)2 = 25 (x + 2)2 + (-1)=5 O (* + 2) + (-1) - 25 (x-1) + ( + 2) = 5
​
Mathematics
1 answer:
natali 33 [55]3 years ago
8 0

Given:

The center of the circle = (-2,1).

Circle passes through the point (-5,3).

To find:

The equation of the circle.

Solution:

Radius is the distance between the center of the circle and any point on the circle. So, radius of the circle is the distance between the points (-2,1) and (-5,3).

Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

r=\sqrt{(-5-(-2))^2+(3-1)^2}

r=\sqrt{(-5+2)^2+(2)^2}

r=\sqrt{(-3)^2+(2)^2}

On further simplification, we get

r=\sqrt{9+4}

r=\sqrt{13}

The standard form of a circle is:

(x-h)^2+(y-k)^2=r^2

Where, (h,k) is the center of the circle and r is the radius of the circle.

Substitute h=-2, k=1 and r=\sqrt{13}.

(x-(-2))^2+(y-1)^2=(\sqrt{13})^2

(x+2)^2+(y-1)^2=13

Therefore, the equation of the circle is (x+2)^2+(y-1)^2=13.

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