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Vladimir [108]
3 years ago
15

To hang lights up on his house.Garrett place is a 14 foot ladder 4 feet from the base of the house. How high up the house will t

he ladder reach
Mathematics
2 answers:
Svetach [21]3 years ago
7 0

Answer: 13.42 feet

Step-by-step explanation:

Given : To hang lights up on his house.Garrett place is a 14 foot ladder 4 feet from the base of the house.

Since house is standing vertical to to ground making a right angles , so the triangle made by ladder must be a right triangle, where ladder is a hypotenuse.

Let h be the height of the house where the ladder reach.

By Pythagoras Theorem , we have

x^2+4^2=14^2\\\\\Rightarrow\ x^2+16=196\\\\\Rightarrow\ x^2=196-16\\\\\Rightarrow\ x^2 =180\\\\\Rightarrow\ x=\sqrt{180}=13.416407865\approx13.42\text{ feet}

Hence, the height of the house where the ladder reach= 13.42 feet

Mariulka [41]3 years ago
6 0

This seems like a right triangle problem.

So assuming 14 feet is the hypotenuse and 4 feet is a leg of the right triangle, we can use the pythagorean theorem (a^{2} +b^{2} =c^{2}) to solve for the height of the house, in which we shall name it x.

So, the equation is 4^{2} +x^{2} =14^{2}.

Solve for x:

16+x^{2}= 196

x^{2}= 196-16

x^{2}= 180

x = 6√5 feet


Hope this helps!

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Answer:

a) \simeq 0.3012   b) \simeq 0.0494 c) \simeq 0.2438

Step-by-step explanation:

Rate of collision,

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So, the Poisson distribution for the random variable no. of collisions per month (X) is given by,

          P(X =x) = \frac{e^{-\lambda}\times {\lambda}^{x}}}{x!}


                                                           for x ∈ N ∪ {0}

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Putting X = 0 in (1) we get,

         P(X = 0) = \frac{e^{-0.3}\times {\0.3}^{0}}{0!}


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P(2 collisions in 2 month period)

                =0.2222454662^{2}

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1 collision in 6 months period means

                                \frac{1}{6} collision per month

Now, P(1 collision in 6 months period)

= P( X = 1/6]  (which is to be estimated)

=\frac {P(X=0)\times 5 + P(X =1)\times 1}{6}

= \frac {0.7408182207 \times 5 + 0.2222454662 \times 1}{6}[/tex]

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So,

P(1  collision in 6 month period)

  =  0.6543894283^{6}

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So,

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so,

P(1 or fewer collision in 6 months period)

= (8) + (7 ) = 0.0785267444 +0.1652988882

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