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mart [117]
3 years ago
8

A bag contains 10 marbles: 2 are green, 4 are red, and 4 are blue. Tammy chooses a marble at random, and without putting it back

, chooses another one at random. What is the probability that both marbles she chooses are blue?
Mathematics
1 answer:
erastovalidia [21]3 years ago
8 0
There are 10 marbles, out of these 10 there are 4.

The probability of her picking a blue marble is 4/10

This can be simplified to 2/5
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Part A: If (72)x = 1, what is the value of x? Explain your answer. (5 points)
vichka [17]

Answer:

see below

Step-by-step explanation:

Part A:  (72)^x = 1

Take the log base 72 of each side

log72(72^x) = log 72(1)

We know log a^b = b log a

x log72(72) = log72(1)

x =  log72(1)

x = 0

Part A:  (70)^x = 1

Take the log base 70 of each side

log70(70^x) = log70(1)

We know log a^b = b log a

x log70(70) = log70(1)

x =  log70(1)

x = 0

7 0
3 years ago
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LenKa [72]

Answer:

68/.75

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7 0
2 years ago
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suter [353]

Answer:

Its A

Step-by-step explanation:

6 0
2 years ago
Please only answer if you're 100% sure it's correct. Thank you. (It's pretty easy.)
Julli [10]

Answer:

2x-7, 2x-7=14, 2+7

Step-by-step explanation:

I am 99% sure these are correct

7 0
3 years ago
Consider the steps for determining the quotient of 12/x-4 / 4/x-4
Ierofanga [76]

Answer:

Quotient = 3

Step-by-step explanation:

We need to solve the given expression :

\dfrac{\dfrac{12}{x-4}}{\dfrac{4}{x-4}}

It can be done as follows :

As, \dfrac{\dfrac{a}{b}}{\dfrac{c}{d}}=\dfrac{a}{b}\times \dfrac{d}{c}

So,

\dfrac{\dfrac{12}{x-4}}{\dfrac{4}{x-4}}=\dfrac{12}{x-4}\times \dfrac{x-4}{4}\\\\=\dfrac{12}{4}\\\\=3

Hence, the required quotient is 3.

5 0
3 years ago
Read 2 more answers
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