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Morgarella [4.7K]
3 years ago
13

CHEMISTRY HELP!:

Chemistry
2 answers:
Mamont248 [21]3 years ago
5 0
1 mol of anything has 6.02 * 10^23 items.
4 mol has 4 times as much
C: Answer <<<<< =========
Lana71 [14]3 years ago
3 0

Answer: C. The argon sample would have four times as many atoms as the neon sample.

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number 6.023\times 10^{23} of particles.

1 mole of neon Ne contains=6.022\times 10^{23 atoms

1 mole of argon Ar contains=6.022\times 10^{23  atoms

Thus 4 moles of argon Ar contains=\frac{6.022\times 10^{23}}{1}\times 4=24.09\times 10^{23}  atoms

Thus the argon sample would have four times as many atoms as the neon sample.

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When 2.50 g is burned then in oxygen then 1.25kj of heat is produced.
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A ____usually requires calculations that are too complicated to do by<br>hand. ​
liraira [26]

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computer model

Explanation:

Computer models are cheaper to set up than alternative methods that could be used to predict what will happen in a system, ex. building a prototype. Other benefits include being able to: make alterations and quickly see the outcomes.

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Water boils at rate of ........and freeze at ........
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PLS ANSWER FAST AHAH<br><br> distilled water is a pure substance <br> true or false ?
mr Goodwill [35]

Answer:

True

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3 0
3 years ago
A 3.140 molal solution of NaCl is prepared. How many grams of NaCl are present in a sample containing 2.692 kg of water
S_A_V [24]

Answer:

494.49 g of NaCl.

Explanation:

Data obtained from the question include the following:

Molality of NaCl = 3.140 m

Mass of water = 2.692 kg

Mass of NaCl =.?

Next, we shall determine the number of mole of NaCl in the solution.

Molality is simply defined as the mole of solute per unit kilogram of solvent. Mathematically, it is expressed as

Molality = mole of solute /Kg of solvent

With the above formula, we can obtain the number of mole NaCl in the solution as follow:

Molality of NaCl = 3.140 m

Mass of water = 2.692 kg

Mole of NaCl =..?

Molality = mole of solute /Kg of solvent

3.140 = mole of NaCl /2.692

Cross multiply

Mole of NaCl = 3.140 x 2.692

Mole of NaCl = 8.45288 moles

Finally, we shall covert 8.45288 moles of NaCl to grams. This can be obtained as follow:

Mole of NaCl = 8.45288 moles

Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol

Mass of NaCl =.?

Mole = mass /Molar mass

8.45288 = mass of NaCl /58.5

Cross multiply

Mass of NaCl = 8.45288 × 58.5

Mass of NaCl = 494.49 g.

Therefore, 494.49 g of NaCl are present in the solution.

8 0
4 years ago
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