Answer:
X represents oxygen and Y represents carbon dioxide.
Explanation:
Because in respiration, you consume oxygen and make carbon dioxide whereas, in photosynthesis, the equation is reversed and you use carbon dioxide and make oxygen and glucose.
One isomer is formed
1,1- Dichloroethane is the isomer.
If another hydrogen of c2h5cl is replaced by a chlorine atom to yield c2h4cl2, it would result in one isomer.
- In contrast to 1,2-dichloroethane, which has two chlorine atoms connected to distinct carbon atoms, 1,1-dichloroethane has two chlorine atoms bound to the same carbon atom.
- Isomers are each of two or more compounds having the same formula but various atom arrangements in the molecule and unique characteristics.
<h3>What three types of isomers are there?</h3>
- Chain isomers
- Functional group isomers
- Positional isomers
These are the three different categories of structural isomers.
<h3>How is an isomer recognized?</h3>
- Their bonding patterns and the way they occupy three-dimensional space can be used to distinguish them.
- Determine the bonding patterns of structural (constitutional) isomers.
- Although the atoms in the compounds are the same, their connections create various functional groups.
<h3>What makes isomers significant?</h3>
- Because two isomers might have the same chemical formula but different chemical structures, they are significant.
- The molecule's properties are influenced by its structure.
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Petrol is a conductor of electricity, because it conducts rather than insulates.
The mass of sodium sulphate, Na₂SO₄, required to prepare the solution is 10.65 g
<h3>How to determine the mole of sodium sulphate Na₂SO₄</h3>
- Volume = 250 mL = 250 / 1000 = 0.25 L
- Molarity = 0.3 M
Mole = Molarity x Volume
Mole of Na₂SO₄ = 0.3 × 0.25
Mole of Na₂SO₄ = 0.075 mole
<h3>How to determine the mass of sodium sulphate Na₂SO₄</h3>
- Molar mass of Na₂SO₄ = 142.05 g/mol
- Mole of Na₂SO₄ = 0.075 mole
Mass = mole × molar mass
Mass of Na₂SO₄ = 0.075 × 142.05
Mass of Na₂SO₄ = 10.65 g
Thus, 10.65 g of Na₂SO₄ is needed to prepare the solution.
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