The molar heat capacity of a compound with the formula C2H6SO is 88.0 J/mol-K. The specific heat of this substance is __________
1 answer:
Answer : The specific heat of this substance is, 1.13 J/g.K
Explanation :
Molar heat capacity : It is defined as the amount of heat absorbed by one mole of a substance to raise its temperature by one degree Celsius.
As we are given that the chemical formula of compound is,
First we have to calculate the molar mass of given compound.
Molar mass of =
Molar mass of = 78 g/mol
Now we have to calculate the specific heat of this substance.
Specific heat of this substance =
Specific heat of this substance =
Specific heat of this substance = 1.13 J/g.K
Thus, the specific heat of this substance is, 1.13 J/g.K
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Answer:
(a) 133.33nm
(b) 600nm
(c) 7,600nm
Explanation:
The concentration of Y can be determined by using the formula:
where;
[L] = concentration of the binding ligand.
kd = 400 nm
Thus:
When Y = 0.25; we get :
0.25 (400 + [L]) = [L]
100 + 0.25[L] = [L]
100 = [L] - 0.25 [L]
100 = 0.75 [L]
[L] = 100/0.75
[L] = 133.33 nm
At, Y = 0.6
0.6 (400 + [L]) = [L]
240 + 0.6[L] = [L]
240 = [L] - 0.6 [L]
240 = 0.4 [L]
[L] = 240/0.4
[L] = 600 nm
At, Y = 0.95
0.95 (400 + [L]) = [L]
380 + 0.95[L] = [L]
380 = [L] - 0.95 [L]
380 = 0.05 [L]
[L] = 380/0.05
[L] = 7600 nm