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kirza4 [7]
3 years ago
13

What is 524.47 rounded to the nearest tenth?

Mathematics
1 answer:
Harlamova29_29 [7]3 years ago
7 0
The answer is 524.5. 983.491 rounded to the nearest whole number is 983.
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Hellllllllllp! Someone help
uysha [10]

Answer:

4. (2, 3)

5. (0, 1)

7. (-1, 2)

Step-by-step explanation:

I hope this helps! Have a nice dayy! :)

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I need help in this question please help me!:)
anastassius [24]

Answer:

(0,4) is the y intercept for function A

(0,3) is the y intercept for function B

so function A has the greatest y intercept

Step-by-step explanation:

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2 years ago
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The following are the last 10 run scores Colin got in cricket:
Solnce55 [7]

Answers:

  • a) Mean = 20.4
  • b) New mean = 20

==================================================

Explanation:

To get the mean, we add up the scores and divide by 10 (because there are 10 scores at first)

28+13+4+12+32+22+13+22+26+32 = 204

204/10 = 20.4

The mean is 20.4

------------

For part b), we redo those steps shown above, but tack 16 onto the list. So we'll add up all the values (including that 16 at the end) and divide by 11 this time.

28+13+4+12+32+22+13+22+26+32+16 = 220

220/11 = 20

The new mean is 20.

The new mean is slightly smaller than the old mean. Notice how 16 is smaller than 20.4, so this new score pulls down the mean just a little bit.

6 0
3 years ago
A cooler has 12 apple juices and 15 grape juices. 9 of the apple juices are sugar free and 5 of the grape juices are sugar free.
antoniya [11.8K]
To me: given that the juice is sugar free means that I can ignore the 3 sugar apple juices and the 10 sugr grape juices.

Therefore the field of drinks is 14 sugar free drinks and the changes that it is apple juice, is 9:14 or 9/14.

If, on the other hand, the problem is saying that the juice must be sugar free and also apple, that would be 9/27 or 1/3
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Suppose a marketing company wants to determine the current proportion of customers who click on ads on their smartphones. It was
andrezito [222]

Answer:

The 92% confidence interval for the true proportion of customers who click on ads on their smartphones is (0.3336, 0.5064).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 100, p = 0.42

92% confidence level

So \alpha = 0.08, z is the value of Z that has a pvalue of 1 - \frac{0.08}{2} = 0.96, so Z = 1.75.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.42 - 1.75\sqrt{\frac{0.42*0.58}{100}} = 0.3336

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.42 - 1.75\sqrt{\frac{0.42*0.58}{100}} = 0.5064

The 92% confidence interval for the true proportion of customers who click on ads on their smartphones is (0.3336, 0.5064).

4 0
3 years ago
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