I think it’s D .but I’m not sure
We know that , in a circle radius perpendicular to chord will bisect the chord.
OM=18, so OQ=QM=18/2=9.
Given QU=8
from figure OQU is a right angled triangle , so OU^2=OQ^2 + QU^2
OU^2 = 9*9 + 8*8 = 81+72=153;
OU=sqrt(153) = 12.37 =13(approx);
From given statements of congruent NT and OU will also be congruent or identical. So, NT=OU=13
Answer:
It's C! y = 7
Step-by-step explanation:
Plugged the equation into an online calculator and got that answer :) Have a good day!
Answer: P(x ≥ 47) = 0.25
Step-by-step explanation:
Since the distribution of the life expectancies of a certain protozoan is normal, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = life expectancies of the certain protozoan.
µ = mean
σ = standard deviation
n = number of samples
From the information given,
µ = 46 days
σ = 10.5 days
n = 49
The probability that a simple random sample of 49 protozoa will have a mean life expectancy of 47 or more days is expressed as
P(x ≥ 47) = 1 - P(x < 47)
For x = 47
z = (47 - 46)/(10.5/√49) = 0.67
Looking at the normal distribution table, the probability corresponding to the z score is 0.0.75
P(x ≥ 47) = 1 - 0.75 = 0.25
