Answer:
y = 
Step-by-step explanation:
Given
x(y + 2) = 3x + y ← distribute parenthesis on left side
xy + 2x = 3x + y ( subtract 2x from both sides )
xy = x + y ( subtract y from both sides )
xy - y = x ← factor out y from each term on the left side )
y(x - 1) = x ← divide both sides by (x - 1)
y =
Ok so basically you have to anahajahabdbnxnxkskalakand
U can pick either point to finish
y - 1 = 2(x-1)
y= 2x-2 +1
y = 2x-1
or
y-5 = 2(x-3)
y = 2x-6+5
y = 2x-1
Answer:
a) Эx ∈ R ⊇ x³ = 2
b) ∀x ∈ R, x² ≥ 0
c) Эx ∈ R ⊇ x³ = x
d) ∀x ∈ R, x ≤ x²
Step-by-step explanation:
Given the data in the question;
let us first go through some symbols and their possible meanings;
Э ⇒ there exists
∀ ⇒ for all
∈ ⇒ belongs to or set membership or element of the set
⊇ ⇒ such that
now;
a) There is a number whose cube is equal to 2
let x represent the number; so
Эx ∈ R ⊇ x³ = 2
b) The square of every number is at least 0
x² ≥ 0, ∀x ∈ R
∀x ∈ R, x² ≥ 0
c) There is a number that is equal to its square
Эx ∈ R ⊇ x³ = x
d) Every number is less than or equal to its square.
x ≤ x², ∀x ∈ R
∀x ∈ R, x ≤ x²
