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Setler [38]
3 years ago
7

Hno3 is an arrhenius

Chemistry
1 answer:
sammy [17]3 years ago
3 0
Arrhenius concept just states that if a solution dissociates and forms H+ ions then its an acid, but if it dissociates and forms OH- than it's a base.

So, HNO3 would be classified as an acid
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2Li+2H2O—>2LiOH+H2
taurus [48]

Explanation:

2Li+2H2O—>2LiOH+H2

Calculate the mass of reacted lithium when H2 is 6.02 * 10 ^ 23 molecules.

I really need the answer with all the calculation please.

3 0
2 years ago
The following equation is balanced correctly. 4C2H6 + 7O2 --&gt; 6H2O + 4CO2<br> True <br> False
Ostrovityanka [42]

Answer: False

Explanation:

4C2H6 + 7O2 --> 6H2O + 4CO2

8 Carbons on the reactant side, but 4 Carbons on the Product

24 Hydrogens on Reactant, 12 H on product

But Oxygen is balanced, 14 on each side

4 0
3 years ago
Read 2 more answers
Passing an electric current through a sample of water (H2O) can cause the water to decompose into hydrogen gas (H2) and oxygen g
Andreas93 [3]
2H2O --> 2H2 + O2
The mole H2O:mole O2 ratio is 2:1
Now determine how many moles of O2 are in 50g: 50g × 1mol/32g = 1.56 moles O2
Since 1 mole of O2 was produced for every 2 moles of H2O, we need 2×O2moles = H2O moles
2×1.56 = 3.13 moles H2O
Finally, convert moles to grams for H2O:
3.13moles × 18g/mol = 56.28 g H2O
D) 56.28
7 0
3 years ago
Fill in the blank with the correct answer. The longer the handle the __________ the mechanical advantage and the greater the inc
ASHA 777 [7]

Answer:

Greater

Explanation:

The longer the handle, the greater the mechanical advantage and the greater the increase in force that is applied to the bolt.

Mechanical advantage is the rate at which force is multiplied.

  • It simply compares the output force to the input force.
  • M.A is the force increasing tendency of a tool.
  • The longer  the handle, the more the mechanical advantage and the lesser the applied force.
7 0
2 years ago
What is the volume of 40g of sugar given it’s listed density
lora16 [44]

Answer:

25.157 cm³

Explanation:

Data Given:

Mass of Sugar (m) = 40g

Density of sugar given in literature = 1.59 g/cm³

Volume of Sugar = ?

The formula will be used is

                              d = m/v ........................................... (1)

where

D is density

m is the mass

v is the volume

So

Rearrange the Equation (1)

                              d x v = m

                               v = m/ d         ................................................ (2)

put the given values in Equation  (2)

                       v = 40g / 1.59 g/cm³

                       v = 25.157 cm³

volume of 40 g of sugar = 25.157 cm³

8 0
3 years ago
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