All categories

3 years ago

The following equation is balanced correctly. 4C2H6 + 7O2 --> 6H2O + 4CO2 True False

Chemistry

2 answers:

Romashka-Z-Leto [24]3 years ago

6 0

Wish I knew but u don’t

Ostrovityanka [42]3 years ago

4 0

Answer: False

Explanation:

4C2H6 + 7O2 --> 6H2O + 4CO2

8 Carbons on the reactant side, but 4 Carbons on the Product

24 Hydrogens on Reactant, 12 H on product

But Oxygen is balanced, 14 on each side

You might be interested in

Water (H2O) is a liquid at room temperature. Ammonia (NH3) is a gas at room temperature. Both are polar covalent compounds. Whic

Nat2105 [25]

the answer is: A. Water

8 0

3 years ago

Read 2 more answers

A 3.28 L solution is prepared by dissolving 535 g CaCl2 in water. The molar mass of CaCl2 is 110.98 g. What is the morality of t

andrey2020 [161]

Answer:

1.47 mol/L

Explanation:

Molarity is given as,

Molarity = Moles / Vol in L ------- (1)

Moles of CaCl₂,

Moles = Mass / M.Mass

Moles = 535 g / 110.98 g/mol

Moles = 4.82 mol

Now, putting values in eq. 1.

Molarity = 4.82 mol / 3.28 L

Molarity = 1.47 mol/L

5 0

2 years ago

Ionic solids dissolve in water and break up into their ions. However, some ionic solids only partially dissolve, leaving a signi

Xelga [282]

Answer: The expression of $K_{sp}$ for calcium fluoride is $K_{sp}=[Ca^{2+}][2F^-]^2$

Explanation:

Solubility product is defined as the product of concentration of ions present in a solution each raised to the power its stoichiometric ratio.

The given chemical equation follows:

$CaF_2\rightleftharpoons Ca^{2+}(aq.)+2F^-(aq.)$

1 mole of calcium fluoride produces 1 mole of calcium ions and 2 moles of fluorine ions.

The expression of $K_{sp}$ for above equation follows:

$K_{sp}=[Ca^{2+}][2F^-]^2$

Hence, the expression of $K_{sp}$ for calcium fluoride is $K_{sp}=[Ca^{2+}][2F^-]^2$

4 0

3 years ago

A 1.00-mole sample of C6H12O6 was placed in a vat with 100 g of yeast. If 32.3 grams of C2H5OH was obtained, what was the percen

Rasek [7]

Answer:

y = 35.06 %.

Explanation:

The reaction of fermentation is:

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂ (1)

From the reaction (1) we have that 1 mol of C₆H₁₂O₆ produces 2 moles of C₂H₅OH, then the number of moles of C₂H₅OH is:

$n = \frac{2 moles C_{2}H_{5}OH}{1 mol C_{6}H_{12}O_{6}}*1 mol C_{6}H_{12}O_{6} = 2 moles C_{2}H_{5}OH$

Now, we need to find the mass of C₂H₅OH:

$m = n*M = 2 moles*46.07 g/mol = 92.14 g$

Finally, the percent yield of C₂H₅OH is:

$\% = \frac{32.3 g}{92.14 g}*100 = 35.06 \%$

Therefore, the percent yield of C₂H₅OH is 35.06 %.

I hope it helps you!

6 0

3 years ago

How many grams of solid potassium hypochlorite should be added to 2.00 L of a 0.244 M hypochlorous acid solution to prepare a bu

Olin [163]

Answer:

8.2763 g

Explanation:

Considering the Henderson- Hasselbalch equation for the calculation of the pH of the buffer solution as:

pH=pKa+log[base]/[acid]

Where Ka is the dissociation constant of the acid.

Given that the acid dissociation constant = 3.5×10⁻⁸

pKa = - log (Ka) = - log (3.5×10⁻⁸) = 7.46

Given concentration of acid = [acid] = 0.244 M

pH = 6.733

So,

6.733 = 7.46+log[base]/0.244

[Base] = 0.0457 M

Given that Volume = 2 L

So, Moles = Molarity × Volume

Moles = 0.0457 × 2 = 0.0914 moles

Molar mass of potassium hypochlorite = 90.55 g/mol

Mass = Moles × Molar mass = (0.0914 × 90.55) g = 8.2763 g

7 0

3 years ago