Answer:
The change in internal energy is - 1.19 kJ
Explanation:
<u>Step 1:</u> Data given
Heat released = 3.5 kJ
Volume calorimeter = 0.200 L
Heat release results in a 7.32 °C
Temperature rise for the next experiment = 2.49 °C
<u>Step 2:</u> Calculate Ccalorimeter
Qcal = ccal * ΔT ⇒ 3.50 kJ = Ccal *7.32 °C
Ccal = 3.50 kJ /7.32 °C = 0.478 kJ/°C
<u>Step 3:</u> Calculate energy released
Qcal = 0.478 kJ/°C *2.49 °C = 1.19 kJ
<u>Step 4:</u> Calculate change in internal energy
ΔU = Q + W W = 0 (no expansion)
Qreac = -Qcal = - 1.19 kJ
ΔU = - 1.19 kJ
The change in internal energy is - 1.19 kJ
Answer:
ΔH°_rxn = -195.9 kJ·mol⁻¹
Explanation:
4NH₃(g) + 3O₂(g) ⟶ 2N₂(g) +6H₂O(g)
ΔH°_f/(kJ·mol⁻¹): -45.9 0 0 -241.8
The formula relating ΔH°_rxn and enthalpies of formation (ΔH°_f) is
ΔH°_rxn = ΣΔH°_f(products) – ΣΔH°_f(reactants)
ΣΔH°_f(products) = -6(241.8) = -1450.8 kJ
ΣΔH°_f(reactants) = -4(45.9) = -183.6 kJ
ΔH°_rxn = (-1450.8 + 183.6) kJ = -1267.2 kJ
Answer:
(NH₄)₃PO₄ (l) + Al(NO₃)₃(l) -----------→ AlPO₄(l) + 3NH₄NO₃(l)
Explanation:
Data Give:
Reaction between ammonium phosphate solution and solution of aluminum nitrate
- Write a balanced chemical equation
Details:
To write a balanced chemical equation we have to know formula units of compounds or molecules
Formula units
ammonium phosphate : (NH₄)₃PO₄
aluminum nitrate: Al(NO₃)₃
ammonium nitrate: NH₄NO₃
Now to write a chemical equation
- we have to write the chemical formulas or formula unit of each compound
- write the reactant on left side of the arrow
- write the product on the right side of the arrow
- put a plus sign in 2 reactants and products on each side of the arrow
- balance the equation by putting coefficient with compound formula
- write the phase symbols on the right corner of the compound formula in brackets
So the Reaction will be
(NH₄)₃PO₄ + Al(NO₃)₃ -----------→ AlPO₄ + NH₄NO₃
Now balance the Chemical equation
(NH₄)₃PO₄ + Al(NO₃)₃ -----------→ AlPO₄ + 3NH₄NO₃
Now write the phase Symbols
(NH₄)₃PO₄ (l) + Al(NO₃)₃(l) -----------→ AlPO₄(l) + 3NH₄NO₃(l)
all compounds in the reaction are in liquid form and soluble in water
*** Note:
There is no aluminum nitrite in chemicals formulas
Also ammonium nitrite can not be used in pure isolated form due to its highly instability