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Alex787 [66]
3 years ago
9

Lithium has the electron arrangement 2,1. When lithium forms an ion,

Chemistry
1 answer:
iragen [17]3 years ago
4 0

Answer:

when lithium forms an ion it donates 1 electron

which makes its electron configuration to become 2

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In Chapter 1 of Astrobiology, A Very Short Introduction, the author talks about some properties of one element in particular tha
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Answer:

Carbon

Explanation:

Carbon has four electrons in its valence shell, so it generally shares it in a covalent bond. This element needs four electrons to be stable, so it can form single (such as the bond with hydrogen), double (such as the bond with oxygen) or triple bonds (such as the bond with nitrogen).

It can also form bonds with other carbon, and they can form longs chains, that's why there are a lot of organic compounds (the compounds with carbon). Carbon can form rings too, such as in benzene.

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How do gas particles respond to an increase in volume?
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An increase in the number of gas molecules in the same volume container increases pressure. A decrease in container volume increases gas pressure. An increase in temperature of a gas in a rigid container increases the pressure.
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The Center of the Adam is called
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Answer:

The center of an Atom is called the Nucleus.

Explanation:

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The cells of plant and animals lack nuclei
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That is not true 
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Calculate: A. Mercury has a specific Heat Capacity of 0.14 J/goC. How much heat is needed to raise the thermometer temperature 1
kari74 [83]

Answer:

\boxed {\boxed {\sf 56 \ Joules}}

Explanation:

We are given the mass, specific heat, and temperature, so we must use this formula for heat energy.

q=mc \Delta T

The mass is 5 grams, the specific heat capacity is 0.14 Joules per gram degree Celsius. Let's find the change in temperature.

  • ΔT= final temperature - initial temperature
  • ΔT= 95°C - 15°C = 80°C

We know the variables and can substitute them into the formula.

m= 5 \ g \\c= 0.14 \ J/ g \ \textdegree C \\\Delta T= 80 \ \textdegree C

q= (5 \ g )( 0.14 \ J/ g \ \textdegree C ) ( 80 \ \textdegree C)

Multiply the first numbers. The grams will cancel.

q= 0.7 \ J/ \textdegree C(80 \ \textdegree C )

Multiply again. This time the degrees Celsius cancel.

q= 56 \ J

56 Joules of heat are needed.

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3 years ago
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