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andrew11 [14]
3 years ago
15

Determining the molecular formula of a hydrocarbon with a relative molecular mass of 54​

Chemistry
1 answer:
frez [133]3 years ago
8 0

Answer:

C₄H₆

Explanation:

A hydrocarbon is a molecule that only contains atoms of Carbon and Hydrogen. As you remember, the molar mass of Carbon is 12g/mol and the molar mass of Hydrogen is 1g/mol.

To solve this question we can find the amount of Carbons necessary that doesn't exceed the 54g/mol. That is:

54g/mol / 12g/mol = 4.5

As the molecular formula must be given in whole numbers, the amount of Carbons is 4. This 4 carbons have a mass of:

12g/mol*4 = 48g/mol

And the hydrogens necessaries to suply the molecular mass are:

54 - 48 = 6 hydrogens

That means molecular formula is:

<h3>C₄H₆</h3>
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zhuklara [117]

Answer:

the storm knocked down trees creating a dam blocking the path for water to move

Explanation:

5 0
3 years ago
The quantity of heat required to change the temperature of 1 g of a substance by 1⁰c is defined as
Alex
Specific heat is the quantity of heat required to change the temperature of 1 gram of a substance by 1 degree Celsius. It is the amount per unit mass that is required to raise the temperature by one degree Celsius. Every substance has its own specific heat and each has its own distinct value. The units of specific heat are joules per gram-degree Celsius (J/f C) and sometimes J/Kg K may also be used.
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3 years ago
Glass of orange juice contain 0.90 dL of juice. How many milliliters of orange juice is that?
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.90 dL is 90 mL because 1 dL is 100 mL
6 0
3 years ago
A lightbulb filled with argon gas has a volume of 75 mL at STP. How many moles of argon gas does the lightbulb contain?
Elan Coil [88]

Answer:

0.00335 moles

Explanation:

From the question, Using

PV = nRT................... Equation 1

Where P = pressure, V = Volume, n = number of moles of argon gas, R = Molar  gas constant, T = Temperature.

make n the subject of the equation

n = PV/RT............... Equation 2

Given: P = 1 atm (standard pressure), T = 273 K (standard temperature), V = 75 mL = 0.075 dm³

Constant: R = 0.082 atm·dm³/K·mol

Substitute into equation 2

n = (1×0.075)/(273×0.082)

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4 0
3 years ago
Part A
KonstantinChe [14]

Answer:

The answer to your question is below

Explanation:

A.

[H₃O⁺] = 2 x 10⁻¹⁴ M

pH = ?

Formula

                                    pH = - log [H₃O⁺]

Substitution

                                    pH = - log [2 x 10⁻¹⁴]

Result

                                    pH = 13.7          

B.

[H₃O⁺] = ?

pH = 3.12

Formula

                                   pH = - log [H₃O⁺]

Substitution

                                   3.12 = - log [H₃O⁺]

                                   10^{-3.12} = [H_{3} O^{+}]

Result

                                  [H₃O⁺] = 7.59 M

   

7 0
3 years ago
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