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2 years ago

Determining the molecular formula of a hydrocarbon with a relative molecular mass of 54

Chemistry

1 answer:

frez [133]2 years ago

8 0

Answer:

C₄H₆

Explanation:

A hydrocarbon is a molecule that only contains atoms of Carbon and Hydrogen. As you remember, the molar mass of Carbon is 12g/mol and the molar mass of Hydrogen is 1g/mol.

To solve this question we can find the amount of Carbons necessary that doesn't exceed the 54g/mol. That is:

54g/mol / 12g/mol = 4.5

As the molecular formula must be given in whole numbers, the amount of Carbons is 4. This 4 carbons have a mass of:

12g/mol*4 = 48g/mol

And the hydrogens necessaries to suply the molecular mass are:

54 - 48 = 6 hydrogens

That means molecular formula is:

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A gas has a volume of 590 mL at temperature of -55.0 C. What volume will the gas occupy at 30.0 C show your work

DENIUS [597]

Data:
$V_{initial} = 590\:mL$
$T_{initial} = -55.0^0C$
converting to Kelvin
TK = TC + 273
TK = -55.0 + 273 → TK = 218.0 → $T_{initial} = 218.0\:K$
$V_{final} = ? (in\:milliliters)$
$T_{final} = 30.0^0C$
TK = TC + 273
TK = 30.0 + 273 → TK = 303.0 → $T_{final} = 303.0\:K$

By the first Law of Charles and Gay-Lussac, we have:
$\frac{ V_{i} }{ T_{i} } = \frac{ V_{f} }{ T_{f} }$

Solving:
$\frac{ V_{i} }{ T_{i} } = \frac{ V_{f} }{ T_{f} }$
$\frac{ 590 }{ 218.0 } = \frac{ V_{f} }{ 303.0 }$
Product of extremes equals product of means:
$218.0* V_{f} = 590*303.0$
$218.0 V_{f} = 178770$
$V_{f} = \frac{178770}{218.0}$
$\boxed{\boxed{V_{f} \approx 820.04\:mL}}\end{array}}\qquad\quad\checkmark$

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2 years ago

Which of these are ionic compounds? Check all that apply.

SIZIF [17.4K]

I think the correct answers from the choices listed above are the first, third and the last option. Ionic compounds are compounds that dissociates into ions when in aqueous solution. From the list, NH4Cl, KF and MgO are the ionic compounds. Hope this answers the question.

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2 years ago

Read 2 more answers

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zmey [24]

Answer:

0.125. work- divide the volume value by 1000

873. work- multiply the length value by 100

98100. work- Conversion factor: 1 kg = 100000 cg

1) Centigram = Kilogram * 100000

2) Centigram = 0.981 * 100000

3) Centigram = 98100

285.65. work- 12.5°C + 273.15 = 285.65K

446.85. work- 720K − 273.15 = 446.85°C

346.25. work- 73.1°C + 273.15 = 346.25K

Explanation:

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2 years ago

Las fórmulas actuales de los compuestos propuestos por Dalton

KonstantinChe [14]

Answer:

La teoría atómica de Dalton fue el primer intento completo para describir toda la materia en términos de los átomos y sus propiedades.

Dalton basó su teoría en la ley de la conservación de la masa y la ley de la composición constante.

La primera parte de su teoría establece que toda la materia está hecha de átomos, que son indivisibles.

La segunda parte de su teoría establece que todos los átomos de un elemento dado son idénticos en masa y en propiedades.

La tercera parte de su teoría establece que los compuestos son combinaciones de dos o más tipos diferentes de átomos.

La cuarta parte de su teoría establece que una reacción química es un reordenamiento de átomos.

Partes de su teoría tuvieron que ser modificadas con base en el descubrimiento de las partículas subatómicas y los isótopos.

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2 years ago

Calculate the volume in mL of 0.279 M Ca(OH)2 needed to neutralize 24.5 mL of 0.390 M H3PO4 in a titration.

Vsevolod [243]

The volume of the 0.279 M Ca(OH)₂ solution required to neutralize 24.5 mL of 0.390 M H₃PO₄ is 51.4 mL

<h3>Balanced equation </h3>

2H₃PO₄ + 3Ca(OH)₂ —> Ca₃(PO₄)₂ + 6H₂O

From the balanced equation above,

The mole ratio of the acid, H₃PO₄ (nA) = 2
The mole ratio of the base, Ca(OH)₂ (nB) = 3

<h3>How to determine the volume of Ca(OH)₂ </h3>

Molarity of acid, H₃PO₄ (Ma) = 0.390 M
Volume of acid, H₃PO₄ (Va) = 24.5 mL
Molarity of base, Ca(OH)₂ (Mb) = 0.279 M

Volume of base, Ca(OH)₂ (Vb) =?

MaVa / MbVb = nA / nB

(0.39 × 24.5) / (0.279 × Vb) = 2/3

9.555 / (0.279 × Vb) = 2/3

Cross multiply

2 × 0.279 × Vb = 9.555 × 3

0.558 × Vb = 28.665

Divide both side by 0.558

Vb = 28.665 / 0.558

Vb = 51.4 mL

Thus, the volume of the Ca(OH)₂ solution needed is 51.4 mL

Learn more about titration:

brainly.com/question/14356286

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1 year ago

Determining the molecular formula of a hydrocarbon with a relative molecular mass of 54​

Determining the molecular formula of a hydrocarbon with a relative molecular mass of 54