F= 6m.m2/r^2
F= (6.673x10^-11)(70)(3.32x10^23)/(2.44x10^6)^2
ANS: F= 260 N=2.60x10^2 N
Hi I believe it is b. sorry if this isnt found to be helpful.
The frictional force is too much compared to the gravitational force
Explanation:
This is because of the great amount of frictional force between the book and the wall.
Also, the force of gravity on the book is not high enough to cause motion of the book to slide downs.
Frictional force is a force that opposes motion.
- For the book to slide down, it must overcome the force of friction acting on it opposite to the direction of gravity.
- According to newton's first law 'a body will remain in its state of rest or uniform motion unless acted upon by an external force'.
- Assuming the external force is gravitational force, clearly we see that the force is less than the frictional exerted on the book by pinning it to the wall.
- This frictional force is a static friction that is on a body at rest, it must be overcome by a larger force before motion takes place.
Fr > fg
Fr is the frictional force
fg is the gravitational force
learn more:
Newton laws brainly.com/question/11411375
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The total electrostatic force on charge A is 
Explanation:
The magnitude of the electrostatic force between two charges is given by Coulomb's law:
where:
is the Coulomb's constant
are the two charges
r is the separation between the two charges
Here we have three positively charged particles A,B and C, located at the following positions:

The magnitudes of the three charges are:

The force exerted by B on A is to the left (because the force between two positive charges is repulsive), and the force exerted by C on A is also to the left (also repulsive). Therefore, the net force on A is just the sum of the two forces exerted by charges B and C:

Learn more about electric force:
brainly.com/question/8960054
brainly.com/question/4273177
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