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ra1l [238]
3 years ago
12

A flat sheet is in the shape of a rectangle with sides of lengths 0.400 m and 0.600 m. The sheet is immersed in a uniform electr

ic field of magnitude 73.9 N/C that is directed at 20 ∘ from the plane of the sheet. Find the magnitude of the electric fluxthrough the sheet.
Physics
1 answer:
LenaWriter [7]3 years ago
5 0

Answer:

6.07 Nm²/C

Explanation:

L = length of the flat sheet = 0.400 m

w = width of the flat sheet = 0.600 m

Area of the rectangular sheet is given as

A = L w

A = (0.400) (0.600)

A = 0.24 m²

E = magnitude of the electric field in the region = 73.9 N/C

θ = Angle of the electric field relative to normal to the plane of sheet = 90 - 20 = 70 deg

Magnitude of magnetic flux through the sheet can be given as

Φ = E A Cosθ

Inserting the values

Φ = (73.9) (0.24) Cos70

Φ = 6.07 Nm²/C

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A strip of copper 190 µm thick and 4.20 mm wide is placed in a uniform magnetic field of magnitude B = 0.78 T, that is perpendic
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V = 9.682 × 10^(-6) V

Explanation:

Given data

thick = 190 µm

wide = 4.20 mm

magnitude B = 0.78 T

current  i = 32 A

to find out

Calculate V

solution

we know v formula that is

V = magnitude× current / (no of charge carriers ×thickness × e

here we know that number of charge carriers/unit volume for copper = 8.47 x 10^28 electrons/m³

so put all value we get

V = magnitude× current / (no of charge carriers ×thickness × e

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