There's a quick, easy, sloppy way, and there's a good math way.
Here's the good math way:
If the integers are consecutive, then you can call them 'x', (x+1), and (x+2).
We know what their sum is, so let's add them up:
x + (x+1) + (x+2) = 336
x + x+1 + x+2 = 336
Combine the terms that are alike on the left side:
3x + 3 = 336
Subtract 3 from each side: 3x = 333
Divide each side by 3 : <u> x = 111</u>
The integers are<em> 111, 112, </em>and<em> 113</em> .
Answer:
0
Step-by-step explanation:
If the event is not possible it's not going to happen
I think your answer might be the first one
Answer:
(2,3)
Step-by-step explanation:
Y=1/2x+2. Find (-4,0), (0,2)
2x+y=7 Find (0,7), (2,3)
And draw two libes
