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Firdavs [7]
2 years ago
7

A translation moves A(-3,2) to a'(0,0). find b', the image of b(5,4)) under the same translation

Mathematics
1 answer:
statuscvo [17]2 years ago
7 0
The image of b, b', would be (8,2)

hope this helps!
You might be interested in
What is the estimate of 90/7 divided by 1 3/4​
attashe74 [19]

Answer:

7×17/49

Step-by-step explanation:

90/7 × 4/7

90×4 / 7×7

360/49

7 17/49

6 0
3 years ago
Simplify (6 1/4)^4<br> a. 6^4<br> b. 1/6<br> c. 6^16<br> d. 6
Margarita [4]

Answer:

Ok

Step-by-step explanation:

do u mean into bracket 61/4 raised to the power of 4???

7 0
3 years ago
Driver's Delight is considering building a new track. They have a circular space
aleksandr82 [10.1K]

Answer:

<h3>The answer is 471 feet</h3>

Step-by-step explanation:

Since the the track is circular

Circumference of a circle = πd

where

d is the diameter

π = 3.14

From the question

diameter = 150 feet

Circumference = 150π

= 150(3.14)

We have the final answer as

<h3>Circumference = 471 feet</h3>

Hope this helps you

6 0
3 years ago
Read 2 more answers
While researching the cost of school lunches per week across the state, you use a sample size of 45 weekly lunch prices. The sta
Drupady [299]

We assume the lunch prices we observe are drawn from a normal distribution with true mean \mu and standard deviation 0.68 in dollars.


We average n=45 samples to get \bar{x}.


The standard deviation of the average (an experiment where we collect 45 samples and average them) is the square root of n times smaller than than the standard deviation of the individual samples. We'll write


\sigma = 0.68 / \sqrt{45} = 0.101


Our goal is to come up with a confidence interval (a,b) that we can be 90% sure contains \mu.


Our interval takes the form of ( \bar{x} - z \sigma, \bar{x} + z \sigma ) as \bar{x} is our best guess at the middle of the interval. We have to find the z that gives us 90% of the area of the bell in the "middle".


Since we're given the standard deviation of the true distribution we don't need a t distribution or anything like that. n=45 is big enough (more than 30 or so) that we can substitute the normal distribution for the t distribution anyway.


Usually the questioner is nice enough to ask for a 95% confidence interval, which by the 68-95-99.7 rule is plus or minus two sigma. Here it's a bit less; we have to look it up.


With the right table or computer we find z that corresponds to a probability p=.90 the integral of the unit normal from -z to z. Unfortunately these tables come in various flavors and we have to convert the probability to suit. Sometimes that's a one sided probability from zero to z. That would be an area aka probability of 0.45 from 0 to z (the "body") or a probability of 0.05 from z to infinity (the "tail"). Often the table is the integral of the bell from -infinity to positive z, so we'd have to find p=0.95 in that table. We know that the answer would be z=2 if our original p had been 95% so we expect a number a bit less than 2, a smaller number of standard deviations to include a bit less of the probability.


We find z=1.65 in the typical table has p=.95 from -infinity to z. So our 90% confidence interval is


( \bar{x} - 1.65 (.101),  \bar{x} + 1.65 (.101) )


in other words a margin of error of


\pm 1.65(.101) = \pm 0.167 dollars


That's around plus or minus 17 cents.




3 0
3 years ago
Read 2 more answers
Find the midpoint of the segment having endpoints (0 ,1/8) and (-4/5 ,0)
kvasek [131]

Answer:

Mid point of the given end points = (\frac{-2}{5},\frac{1}{16} )

Step-by-step explanation:

Given the end points of the line segment are :

(0, \frac{1}{8}) & (\frac{-4}{5},0)

We will use the mid point formula when two points are: (x₁,y₁) & (x₂,y₂)

mid point = (\frac{x_{1} +x_{2} }{2},\frac{y_{1} +y_{2} }{2} )

now put the value of x₁ = 0

x₂ = \frac{-4}{5}

y₁ = \frac{1}{8}

y₂ = 0

mid point = (\frac{0-\frac{4}{5} }{2},\frac{\frac{1}{8}+0 }{2})

                = (\frac{-2}{5},\frac{1}{16} )

That's the final answer.

3 0
3 years ago
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