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Mashutka [201]
3 years ago
12

Suppose that the scores on a reading ability test are normally distributed with a mean of and a standard deviation of . What pro

portion of individuals score more than points on this test? Round your answer to at least four decimal places.
Mathematics
1 answer:
Gnoma [55]3 years ago
4 0

Answer:

The proportion of individuals score at most 74 points on this test is 70%.

Step-by-step explanation:

The complete question is:

Suppose that the scores on a reading ability test are normally distributed with a mean of 70 and a standard deviation of 8. What proportion of individuals score at most 74 points on this test? Round your answer to at least four decimal places.

Solution:

Let <em>X</em> represent the scores on a reading ability test.

It is provided that X\sim N(70,8^{2}).

Compute the probability that an individuals score is at most 74 points on this test as follows:

P(X\leq 74)=P(\frac{X-\mu}{\sigma}\leq \frac{74-70}{8})

                 =P(Z

Thus, the proportion of individuals score at most 74 points on this test is 70%.

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K/6 + 8 = 5 what does k=?
vesna_86 [32]

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Solve for x: 6x + 1/4 (4x + 3) &gt; 12<br> Ox&gt;<br> 10<br> 7<br> Ox&gt; 2<br> ox= 10<br> X = 2
daser333 [38]

Given:

The inequality is:

6x+\dfrac{1}{4}(4x+3)>12

To find:

The values for x.

Solution:

We have,

6x+\dfrac{1}{4}(4x+3)>12

Using distributive property, we get

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On further simplification, we get

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Divide both sides by 7.

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