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Paha777 [63]
3 years ago
9

TWO MINUTES LEFT ________ __________ is the physical arrangement of devices on a network.

Computers and Technology
1 answer:
coldgirl [10]3 years ago
7 0
A database? I'm not entirely sure, but i think it is called a database.
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1k bits equals to how many bits
ruslelena [56]

Answer:

1000 bits

Explanation:

hope it helps :D

8 0
3 years ago
Write a function called order() thattakes three parameters, and rearranges the integers referred to sothat the largest is first,
gogolik [260]

Answer: The c++ program to implement order() method is given below.

#include <iostream>

using namespace std;

void order(int a, int b, int c);

int main() {

   int x, y, z;

   cout<<"This program displays numbers in descending order."<<endl;

   do

   {

       cout<<"Enter first number"<<endl;

       cin>>x;

       if(x<0)

           cout<<"Invalid input. Enter a positive number."<<endl;

   }while(x<0);

   do

   {

       cout<<"Enter second number"<<endl;

       cin>>y;

       if(y<0)

           cout<<"Invalid input. Enter a positive number."<<endl;

   }while(y<0);

   do

   {

       cout<<"Enter third number"<<endl;

       cin>>z;

       if(z<0)

           cout<<"Invalid input. Enter a positive number."<<endl;

   }while(z<0);

   order(x, y, z);

   return 0;

}

void order(int a, int b, int c)

{

   if((a>b)&&(a>c))

   {  

       cout<<"Numbers in decreasing order are"<<endl;

       cout<<a<<endl;

           if(b>c)

           {

               cout<<b<<endl;        

               cout<<c<<endl;

           }

           else

           {

               cout<<c<<endl;

               cout<<b<<endl;

           }

   }    

   if((b>a)&&(b>c))

   {  

       cout<<"Numbers in decresing order are"<<endl;

       cout<<b<<endl;

           if(a>c)

           {

               cout<<a<<endl;        

               cout<<c<<endl;

           }

           else

           {

               cout<<c<<endl;

               cout<<a<<endl;

           }

   }    

   if((c>b)&&(c>a))

   {  

       cout<<"Numbers in decreasing order are"<<endl;

       cout<<c<<endl;

           if(a>b)

           {

               cout<<a<<endl;        

               cout<<b<<endl;

           }

           else

           {

               cout<<b<<endl;

               cout<<a<<endl;

           }

   }

       

}

OUTPUT

This program displays numbers in descending order.

Enter first number

12

Enter second number

-9

Invalid input. Enter a positive number.

Enter second number

0

Enter third number

55

Numbers in decreasing order are

55

12

0

Explanation:

The method order() is declared as follows.

void order(int a, int b, int c);

The method is declared void since it does not return any value.

This program is designed to accept 0 and positive integers only. This is implemented by do-while loop while taking user input.

The program uses 3 integer variables to store the user input.

int x, y, z;

The method order() is designed to accept 3 integer parameters. This method is called once user enters valid input.

order(x, y, z);

These numbers are compared in order to display them in descending order.

No variable is used for comparison. The method simply compares the numbers and displays them using multiple if-else statements.

4 0
3 years ago
The process of finding the largest and smallest numbers is used frequently in computer applications. Write a C++ program that us
WINSTONCH [101]

Answer:

The program to this question can be given as:

Program:

#include<iostream>  //header file

using namespace std;

int main()    //main method

{

int x[10],i,largest = 0,second_largest=0,n;  //variable

cout << "Enter Number of elements :";  //message

cin>>n;

cout << "Insert array elements :";  //message

for(i=0;i<n;i++)  //insert elements in array

{

cin >>x[i];

}

//Finding Largest element  

for(i=0;i<n;i++)

{

if (x[i]>largest)

{

largest = x[i];

}

}

//finding second largset element

for(i=0;i<n;i++)

{

if (x[i]>second_largest)

{

   if(x[i]==largest)

   {

   continue;   //Ignoring largest in order to get second largest

   }

   second_largest=x[i];

}

}

//print value

cout <<"Largest Number:"<<largest<<endl;

cout <<"Second Largest Number:"<<second_largest;

return 0;

}

Output:

Enter Number of elements :5

Insert array elements :33

45

75

87

23

Largest Number:87

Second Largest Number:75

Explanation:

In the above program firstly we define the header file then we define the main method in the main method we define the array and other variables. We first input the number for the size of the array. Then we insert array elements after inserting array elements we search the largest number and the second largest number in the array. To search the largest number in the array we use the loop. To search the first largest number we define a condition that array is greater than the largest number and store the value into the largest variable. Then we check the second largest number in the array for this we use two conditions that are array is greater than the second largest number in this we use another condition that is array is equal to the largest number. If the inner condition is true then it will move forward and end of an inner condition. In the outer condition, the value will be stored on the second_largest variable all the conditions will be done inner the loop. At the last we print values.

3 0
3 years ago
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