Express √3 + i in polar form:
|√3 + i| = √((√3)² + 1²) = √4 = 2
arg(√3 + i) = arctan(1/√3) = π/6
Then
√3 + i = 2 (cos(π/6) + i sin(π/6))
By DeMoivre's theorem,
(√3 + i)³ = (2 (cos(π/6) + i sin(π/6)))³
… = 2³ (cos(3 • π/6) + i sin(3 • π/6))
… = 8 (cos(π/2) + i sin(π/2))
… = 8i
Answer:
C
Step-by-step explanation:
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Answer:
(x + 2)²(x - 3)² = 0
Step-by-step explanation:
Since we have a degree of 2 and double of the same roots, we know that each root would have a multiplicity of 2. Therefore, our answer is(x + 2)²(x - 3)² = 0
It will be D. because you have to add the like terms which is 13 + 5 which will be 18 and so 10p doesn't have no like terms it just stays the same so it will be 10p+18
