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2 years ago

Identify the vertex and axis symmetry of the graph y=-2(x+1)^2+5

1 answer:

5 0

<span>y=2(x+1)^2-5.
axis of symmetry is x+1=0...or....x=-1...then y=-5 .hence vertex is (-1,-5)
y =-5 for x=-1 is the minimum value .hence direction of opening is upwards for the curve.</span>

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Answer:

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$x_2=\frac{5-\sqrt{33}}{4}$ ≈-0.19

Step-by-step explanation:

To solve this problem you must apply the proccedure shown below:

1. You have that the quadratic formula is:

$x=\frac{-b+/-\sqrt{b^{2}-4ac}}{2a}$

2. To solve the quadratic equation you must substitute the values. So, you have that:

Rewrite the equation:

$2x^{2}-5x-1=0$

$a=2\\b=-5\\c=-1$

Then you have:

$x=\frac{-(-5)+/-\sqrt{(-5)^{2}-4(2)(-1)}}{2(2)}$

3. Therefore, you obtain the following result:

$x_1=\frac{5+\sqrt{33}}{4}$ ≈2.69

$x_2=\frac{5-\sqrt{33}}{4}$ ≈-0.19

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