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Daniel [21]
3 years ago
12

I need help with this please.

Mathematics
1 answer:
Setler [38]3 years ago
5 0
A. 170 students out of the 230 students love both biking and skating (to make it easier, the percentage is about 0.74).
I am sorry if I cannot solve the other half of your question
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20c + 8d +10c - 5d<br><br><br> please answer you would get 15 points!
Rudik [331]
I think 30c+3d would be the correct answer.
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What is the product of 1 2/3 and -3 1/2?
svp [43]
-5.83 the 3 is repeated
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How many times can 224 go into 1400?
marshall27 [118]
Its 1400 divided by 224 so it will be 6.25 times

8 0
4 years ago
Suppose each of the following data sets is a simple random sample from some population. For each dataset, make a normal QQ plot.
adell [148]

Answer:

a) For this case the histogram is not too skewed and we can say that is approximately symmetrical so then we can conclude that this dataset is similar to a normal distribution

b) For this case the data is skewed to the left and we can't assume that we have the normality assumption.

c) This last case the histogram is not symmetrical and the data seems to be skewed.

Step-by-step explanation:

For this case we have the following data:

(a)data = c(7,13.2,8.1,8.2,6,9.5,9.4,8.7,9.8,10.9,8.4,7.4,8.4,10,9.7,8.6,12.4,10.7,11,9.4)

We can use the following R code to get the histogram

> x1<-c(7,13.2,8.1,8.2,6,9.5,9.4,8.7,9.8,10.9,8.4,7.4,8.4,10,9.7,8.6,12.4,10.7,11,9.4)

> hist(x1,main="Histogram a)")

The result is on the first figure attached.

For this case the histogram is not too skewed and we can say that is approximately symmetrical so then we can conclude that this dataset is similar to a normal distribution

(b)data = c(2.5,1.8,2.6,-1.9,1.6,2.6,1.4,0.9,1.2,2.3,-1.5,1.5,2.5,2.9,-0.1)

> x2<- c(2.5,1.8,2.6,-1.9,1.6,2.6,1.4,0.9,1.2,2.3,-1.5,1.5,2.5,2.9,-0.1)

> hist(x2,main="Histogram b)")

The result is on the first figure attached.

For this case the data is skewed to the left and we can't assume that we have the normality assumption.

(c)data = c(3.3,1.7,3.3,3.3,2.4,0.5,1.1,1.7,12,14.4,12.8,11.2,10.9,11.7,11.7,11.6)

> x3<-c(3.3,1.7,3.3,3.3,2.4,0.5,1.1,1.7,12,14.4,12.8,11.2,10.9,11.7,11.7,11.6)

> hist(x3,main="Histogram c)")

The result is on the first figure attached.

This last case the histogram is not symmetrical and the data seems to be skewed.

7 0
3 years ago
How many of the numbers from the set $\{1,\ 2,\ 3,\ldots,\ 50\}$ have a perfect square factor other than one?
Novay_Z [31]

Answer:

2^2 ( 1,2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12)  =  4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44,48

3^2(1,2,3, 5)   =  9, 18, 27, 45

5^2(1, 2)  = 25, 50

7^2  = 49

19  numbers

Step-by-step explanation:

5 0
3 years ago
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