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3 years ago

The difference between 4,632 and 20,000 is what number

Mathematics

2 answers:

zysi [14]3 years ago

3 0

The difference is subtraction.

20,000 - 4,632 = 15,368

Answer: 15,368

Naddik [55]3 years ago

3 0

If you want to find the difference of something you subtract so the solution would just be to subtract those two numbers.

20,000-4632=15,368

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Answer:

Step-by-step explanation:

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180 -154 = 26

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2 years ago

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3 years ago

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3 years ago

Which expression is equivalent to (16 x Superscript 8 Baseline y Superscript negative 12 Baseline) Superscript one-half?.

loris [4]

To solve the problem we must know the Basic Rules of Exponentiation.

<h2>Basic Rules of Exponentiation</h2>

$x^ax^b = x^{(a+b)}$
$\dfrac{x^a}{x^b} = x^{(a-b)}$
$(a^a)^b =x^{(a\times b)}$
$(xy)^a = x^ay^a$

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The solution of the expression is $\dfrac{4x^4}{y^6}$ .

<h2>Explanation</h2>

Given to us

$(16x^8y^{12})^{\frac{1}{2}}$

Solution

We know that 16 can be reduced to $2^4$ ,

$=(2^4x^8y^{12})^{\frac{1}{2}}$

Using identity $(xy)^a = x^ay^a$ ,

$=(2^4)^{\frac{1}{2}}(x^8)^{\frac{1}{2}}(y^{12})^{\frac{1}{2}}$

Using identity $(a^a)^b =x^{(a\times b)}$ ,

$=(2^{4\times \frac{1}{2}})\ (x^{8\times\frac{1}{2}})\ (y^{12\times{\frac{1}{2}}})$

Solving further

$=2^2x^4y^{-6}$

Using identity $\dfrac{x^a}{x^b} = x^{(a-b)}$ ,

$=\dfrac{2^2x^4}{y^6}$

$=\dfrac{4x^4}{y^6}$

Hence, the solution of the expression is $\dfrac{4x^4}{y^6}$ .

Learn more about Exponentiation:

brainly.com/question/2193820

8 0

2 years ago

Homework #16- Complete all odd questions.

katen-ka-za [31]

Question 1)

Given

The expression is 5xy

To determine

Find the value of 5xy if x = 2 and y = 3

5xy

substitute x = 2 and y = 3

5xy = 5(2)(3)

= 5(6)

= 30

Therefore, the value of 5xy = 30 if x = 2 and y = 3.

<em>Note: your remaining questions are not mentioned. But, the procedure may remain the same. Hopefully, your concept will be cleared anyway.</em>

8 0

2 years ago