|x|=absoulte value of x which means whatever x is, make it positive
so first solve any division/multiplication
the only one is 12/46=6/23
so we do the absoulte value signs
-3+45-(-14)
-(-14)=+14
-3+45+14=56
absoulute value of 56=56
56+(-|-87+6/23|)
-87+6/23=-86 and 17/23
absoulte value of -86 and 17/23=86 and 17/23
there is a negative sign in front of the absoulte vaulue so make it negative
56-86 and 17/23=-30 and 17/23 or about -30.73913
Circle: x^2+y^2=121=11^2 => circle with radius 11 and centred on origin.
g(x)=-2x+12 (from given table, find slope and y-intercept)
We can see from the graphics that g(x) will be almost tangent to the circle at (0,11), and that both intersection points will be at x>=11.
To show that this is the case,
substitute g(x) into the circle
x^2+(-2x+12)^2=121
x^2+4x^2-2*2*12x+144-121=0
5x^2-48x+23=0
Solve using the quadratic formula,
x=(48 ± √ (48^2-4*5*23) )/10
=0.5058 or 9.0942
So both solutions are real and both have positive x-values.
Answer:
Step-by-step explanation:
Straight line is an angle whose vertex point(O) has a value of 180. The arms (OA & OB) of the straight line angle lies opposite to each other from the vertex point
Sum of all the angles in a straight line = 180
From this you can find the value of unknown angle, if other angles are given.
∠AOC + ∠BOC = 180
