A) zeroes
P(n) = -250 n^2 + 2500n - 5250
Extract common factor:
P(n)= -250 (n^2 - 10n + 21)
Factor (find two numbers that sum -10 and its product is 21)
P(n) = -250(n - 3)(n - 7)
Zeroes ==> n - 3 = 0 or n -7 = 0
Then n = 3 and n = 7 are the zeros.
They rerpesent that if the promoter sells tickets at 3 or 7 dollars the profit is zero.
B) Maximum profit
Completion of squares
n^2 - 10n + 21 = n^2 - 10n + 25 - 4 = (n^2 - 10n+ 25) - 4 = (n - 5)^2 - 4
P(n) = - 250[(n-5)^2 -4] = -250(n-5)^2 + 1000
Maximum ==> - 250 (n - 5)^2 = 0 ==> n = 5 and P(5) = 1000
Maximum profit =1000 at n = 5
C) Axis of symmetry
Vertex = (h,k) when the equation is in the form A(n-h)^2 + k
Comparing A(n-h)^2 + k with - 250(n - 5)^2 + 1000
Vertex = (5, 1000) and the symmetry axis is n = 5.
Answer:
1038
Step-by-step explanation:
you add 308 and 730
Answer:
A die has 6 numbers.
So 6 numbers them being
1, 2, 3, 4, 5, 6
There’s only one number greater then 5 which is 6.
Since its 6 numbers, a die has a 1/6 chance of getting your desired number.
So it’s a 1/6 chance.
A diagram must be provided along with the question above. Based on my research, here is what I got.
<span>100 pi is the area of the entire circle
That makes :
</span><span>∠ A = 45°/360 = 1/8
</span> 100pi/8 = 25 pi / 2
The answer is option D)25π over 2. I hope this answer helps.
The number of combinations will be 6 for even numbers.
<h3>What is the combination?</h3>
The arrangement of the different things or numbers in a number of ways is called the combination.
Given that:-
- A dial combination lock has dials numbered 0 to 5. The lock is set to an even number. How many different numbers could it be?
The total sample numbers are from 0 to 5 which are 0,1,2,3,4,5.
The even numbers are 0,2,4.
The combinations will be given by:-
C = 3!
C = 3 x 2 x1
C = 6
Therefore the number of combinations will be 6 for even numbers.
To know more about Combinations follow
brainly.com/question/295961
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