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garik1379 [7]
3 years ago
9

Please help me, I am so confused. Thanks​

Mathematics
1 answer:
miskamm [114]3 years ago
8 0

Answer:

c. 80

Step-by-step explanation:

cos x = sin(x-70)

cos x = cos [90-(x-70)]

cos x = cos (90-x +70)

cos x = cos 160 -x

x= 160-x

2x = 160

x =80

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An emergency room (ER) nurse noticed that there are an unusually high number of motor-vehicle accident injuries in the month of
Dmitrij [34]

4800 patients

Step-by-step explanation:

120 of 1000 means 12%

12% of 40000 is 4800

7 0
3 years ago
Solve the triangle. Round your answers to the nearest tenth.
Tresset [83]

Answer:

<B = 47°

<C = 28°

b = AC = 28.0

Step-by-step explanation:

Given:

∆ABC

AB = c = 18

BC = a = 37

<A = 105°

Required:

Length of AC = b

measure of angle B and angle C

SOLUTION:

==>Use the sine rule, sin A/a = sinC/c to find the angle of C:

SinA = sin(105) = 0.9659

a = 37

sinC = ?

c = 18

0.9659/37 = sinC/18

Cross multiply

0.9659*18 = 37*sinC

17.3862 = 37*sinC

Divide both sides by 37

17.3862/37 = sinC

0.4699 = sinC

sinC = 0.4699

C = Sin-¹(0.4699)

C = 28.0° (nearest tenth)

==>Find angle B using sum of angles in a triangle:

Angle B = 180 - (105+28)

Angle B = 180 - 133

Angle B = 47°

==>Find length of b using sine rule, b/sinB = c/sinC:

SinC = sin(28) = 0.4695

SinB = sin(47) = 0.7314

c = 18

b = ?

b/0.7314 = 18/0.4695

Cross multiply

b*0.4695 = 18*0.7314

b*0.4695 = 13.1652

Divide both sides by 0.4695

b = 13.1652/0.4695

b = 28.0 (nearest tenth)

6 0
3 years ago
On a coordinate plane, a triangle has points A prime (1, 2), B prime (3, negative 3), C prime (negative 1, negative 3). Triangle
Volgvan

Answer:

A'(5.5, -4.2), B'(7.5, -9.2), C'(3.5, -3.2)

Step-by-step explanation:

I really do hope I understood you correctly. I figured that the rule would have to be added to each point. If those are wrong, try subtracting the rule.

Again, I'm not trying to take your points and leave you with a wrong answer. I really did give it my best.

4 0
3 years ago
Read 2 more answers
The area of a rectangle is 2x*2-13x+12 and another area is 6x^2-13x+21, what is the combined area of both rectangles?
saul85 [17]

Answer:

8x^2 - 26x + 33

Step-by-step explanation:

Add the expressions.

2x^2 - 13x + 12 + 6x^2 - 13x + 21 =

= 2x^2 + 6x^2 - 13x - 13x + 12 + 21

= 8x^2 - 26x + 33

8 0
3 years ago
Convert to standard form: y=1/3x + 3/4
ira [324]

Answer:

4x-12y=9

Step-by-step explanation:

y=1/3 x + 3/4

1/3 x-y=3/4

(x-3y)/3=3/4

4(x-3y)=3×3

4x-12y=9

6 0
2 years ago
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