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Dovator [93]
4 years ago
11

Consider julie's scores on three final exams (x), along with the class means and standard deviations: subject x mean standard de

viation history 75 70 5 english 92 90 10 math 80 70 3 science 84 70 7 compared to the other students who took the test, in what class is was julie's highest score?
Mathematics
1 answer:
Viktor [21]4 years ago
3 0

Consider julie's scores on three final exams (x), along with the class means and standard deviations: subject x mean standard deviation history 75 70 5 english 92 90 10 math 80 70 3 science 84 70 7 compared to the other students who took the test, in what class is was julie's highest score?

Answer: In order to find in what class Julie's has scored highest, we need to find the z score corresponding to Julie's score. The subject who has the highest z score will indicate that Julie has scored highest in that subject.

Z score for History:

z=\frac{75-70}{5} =1

z score for english:

z=\frac{92-90}{10} =0.2

z score for math:

z=\frac{80-70}{3} =3.33

z score for science:

z=\frac{84-70}{7} =2

Since the z score for Math is highest, therefore, in Math class Julie's score is highest.

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Simplify expression x8y-26/x14y-5 × x-39y-21
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The simplified form of the expression is x^{-45} y^{-42}

<h3>Simplifying an expression</h3>

From the question, we are to simplify the given expression

The given expression is

\frac{x^{8}y^{-26}  }{x^{14}y^{-5}  } \times x^{-39} y^{-21}

The expression can be simplified as shown below

\frac{x^{8}y^{-26}  }{x^{14}y^{-5}  } \times x^{-39} y^{-21}

\frac{x^{8} \times x^{-39} \times  y^{-26} \times  y^{-21}  }{x^{14} \times y^{-5}  }

\frac{x^{8+-39} \times  y^{-26+-21}  }{x^{14} \times y^{-5}  }

\frac{x^{8-39} \times  y^{-26-21}  }{x^{14} \times y^{-5}  }

\frac{x^{-31} \times  y^{-47}  }{x^{14} \times y^{-5}  }

Then,

\frac{x^{-31} }{x^{14} } \times \frac{ y^{-47} }{ y^{-5} }

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x^{-31-14} \times y^{-47+5}

x^{-45} \times y^{-42}

x^{-45} y^{-42}

Hence, the simplified form of the expression is x^{-45} y^{-42}

Learn more on Simplifying an expression here: brainly.com/question/2320607

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