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3 years ago

How can you determine wether an equation has infinitely many or no solutions?

1 answer:

4 0

If an equation is infinitely the answers end up being the same no matter what you do so for example if you end up with 6=6 that is infinitely and no solution is where you cant get an answer and/or the equation is not true.

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Which of the following is the equation for the graph shown?a. x^2/144+y^2/95=1b. x^2/144-y^2/95=1c. x^2/95+y^2/144=1d. x^2/95-y^

Andrews [41]

e follSOLUTION

Given the question in the image, the following are the solution steps to answer the question

STEP 1: Write the general equation of an ellipse

$\frac{\mleft(x-h\mright)^2}{a^2}+\frac{(y-h)^2}{b^2^{}}=1$

STEP 2: Identify the parameters

the length of the major axis is 2a

the length of the minor axis is 2b

$\begin{gathered} 2a=24,a=\frac{24}{2}=12 \\ 2b=20,b=\frac{20}{2}=10 \end{gathered}$

STEP 3: Get the equation of the ellipse

$\begin{gathered} By\text{ substitution,} \\ \frac{(x-h)^2}{a^2}+\frac{(y-h)^2}{b^2}=1 \\ \frac{(x-0)^2}{12^2}+\frac{(y-0)^2}{10^2}=1=\frac{x^2}{144}+\frac{y^2}{100}=1 \end{gathered}$

STEP 4: Pick the nearest equation from the options,

Hence, the equation of the ellipse in the image is given as:

$\frac{x^2}{144}+\frac{y^2}{95}=1$

OPTION A

8 0

2 years ago

Use the method of completing the square to transform the quadratic equation into the equation form (x + p)2 = q. 3 + x - 3x2 = 9

Triss [41]

To <span>transform the quadratic equation into the equation form (x + p)2 = q we shall proceed as follows:
3+x-3x^2=9
putting like terms together we have:
-3x^2+x=6
dividing through by -3 we get:
x^2-x/3=-2
but
c=(b/2a)^2
c=(-1/6)^2=1/36
thus the expression will be:
x^2-x/3+1/36=-2+1/36
1/36(6x-1)</span>²=-71/36

the answer is:
1/36(6x-1)²=-71/36

7 0

3 years ago

Select the correct answer.

bezimeni [28]

I think it would be A

5 0

4 years ago

Help me pleas. And no bots. :)

andreev551 [17]

Answer:

1st is B

2nd is A

3rd is D

last is C

4 0

3 years ago

Read 2 more answers

Assume that in january 2013, the average house price in a particular area was $289,400. in january 2000, the average price was $

PtichkaEL [24]

The problem is an arithmetic sequence with:
a₁ = 206,300
an = 208,400

n = 2013 - 2000
n = 13

To find the annual increase, use this following formula
an = a₁ + d(n - 1)
d represents the annual increase

Input the numbers
an = a₁ + d(n - 1)
289,400 = 206,300 + d(13 - 1)
289,400 = 206,300 + 12d
289,400 - 206,300 = 13d
83,100 = 12d
12d = 83,100
d = 83,100/12
d = 6,925

The annual increase is $6925

7 0

3 years ago