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Alja [10]
3 years ago
12

Round 489 to the nearest ten​

Mathematics
2 answers:
Helga [31]3 years ago
7 0

Answer:

<em>5</em><em>0</em><em>0</em>

Step-by-step explanation:

<em>4</em><em>8</em><em>9</em><em> </em><em>w</em><em>h</em><em>e</em><em>n</em><em> </em><em>r</em><em>o</em><em>u</em><em>n</em><em>d</em><em>e</em><em>d</em><em> </em><em>t</em><em>o</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>n</em><em>e</em><em>a</em><em>r</em><em>e</em><em>s</em><em>t</em><em> </em><em>1</em><em>0</em><em> </em><em>i</em><em>s</em><em> </em><em>5</em><em>0</em><em>0</em>

Lynna [10]3 years ago
6 0
Your answer is 500. The tenths place is above half so that wouls round up to 500.
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Find the maxium valve C=6x+2y. Subject to the following constraints x≥0, x≤5, y≥0, 4x-y≥1
Vadim26 [7]

Answer:

The maximum value of C is 68

Step-by-step explanation:

we have the following constraints

x\geq 0 ----> constraint A

x\leq 5 ----> constraint B

y\geq 0 ----> constraint C

4x-y\geq 1 ----> constraint D

Find out the area of the feasible region, using a graphing tool

The vertices of the feasible region are

(0,0),(5,19),(5,0)

see the attached figure

To find out the maximum value of the objective function C, substitute the value of x and the value of y of each vertex in the objective function and then compare the results

C=6x+2y

For (0,0) -----> C=6(0)+2(0)=0

For (5,19) -----> C=6(5)+2(19)=68

For (5,0) -----> C=6(5)+2(0)=30

therefore

The maximum value of C is 68

8 0
3 years ago
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garik1379 [7]
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3 years ago
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Serggg [28]
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6 less than (-6) 2 times a number (2 time x) is greater than (>) 8 (8)

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2x>14
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jasenka [17]

Answer:x=17

Step-by-step explanation:

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8 0
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Answer:

Look Down

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3 years ago
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