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Dvinal [7]
2 years ago
7

42x^2 + 32 - 18 =6062

Mathematics
1 answer:
Elenna [48]2 years ago
4 0
Okay, we start with 42x^2 + 32 - 18 = 6062. To solve single-variable equations like this one, we want to isolate the x by moving all of the other numbers to the other side of the equation. We need to first subtract 32 and 18, and that equals 14. Now our problem looks like this, 42x^2 + 14 = 6062. Since 14 is the only other number on the left side, we subtract four from both sides! This gives us 42x^2 + 14 - 14 = 6062 - 14, so 42x^2 = 6062. Now to find x, we want to just have one x on the left side instead of 42, so we divide the equation by 42 to find that 42x^2/42 = 6048/42, so x = 12
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Which expression has the same value as the one below?<br>10 +(-3)​
Anna35 [415]
10+ (-3)=10-3=7 is the answer
4 0
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Read 2 more answers
What is the Answer For 4x y = -10
Katena32 [7]
Xy = -10/ 4
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So, xy = -2.5
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3 years ago
a rectangular prism is 5 inches wide and has a volume of 30 cubic inches if the width of the rectangular prism is doubled what i
Nimfa-mama [501]
Volume = W*L*H
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8 0
2 years ago
Solve 3x + 7 &gt; -x - 9. Show each step of your work.
Kruka [31]

Answer:

x > -4

Step-by-step explanation:

Inequalities like these are solved the same way equations are solved, except when multiplying both sides you flip the less than/greater than sign:

3x + 7 > -x -9

3x + 7 - 7 > -x -9 -7     Subtract 7 from both sides

3x > -x -16

3x + x > -x -16 + x     add x to both sides

4x > -16

\frac{4x}{4} > \frac{-16}{4}     divide both sides by 4

x > -4

In this case the inequality sign did not have to be flipped since we never multiply both sides by a negative number.

3 0
2 years ago
A ball is thrown into the air by a baby alien on a planet in the system of Alpha Centauri with a velocity of 30 ft/s. Its height
Crank

Answer:

a) h = 0.1: \bar v = -11\,\frac{ft}{s}, h = 0.01: \bar v = -10.1\,\frac{ft}{s}, h = 0.001: \bar v = -10\,\frac{ft}{s}, b) The instantaneous velocity of the ball when t = 2\,s is -10 feet per second.

Step-by-step explanation:

a) We know that y = 30\cdot t -10\cdot t^{2} describes the position of the ball, measured in feet, in time, measured in seconds, and the average velocity (\bar v), measured in feet per second, can be done by means of the following definition:

\bar v = \frac{y(2+h)-y(2)}{h}

Where:

y(2) - Position of the ball evaluated at t = 2\,s, measured in feet.

y(2+h) - Position of the ball evaluated at t =(2+h)\,s, measured in feet.

h - Change interval, measured in seconds.

Now, we obtained different average velocities by means of different change intervals:

h = 0.1\,s

y(2) = 30\cdot (2) - 10\cdot (2)^{2}

y (2) = 20\,ft

y(2.1) = 30\cdot (2.1)-10\cdot (2.1)^{2}

y(2.1) = 18.9\,ft

\bar v = \frac{18.9\,ft-20\,ft}{0.1\,s}

\bar v = -11\,\frac{ft}{s}

h = 0.01\,s

y(2) = 30\cdot (2) - 10\cdot (2)^{2}

y (2) = 20\,ft

y(2.01) = 30\cdot (2.01)-10\cdot (2.01)^{2}

y(2.01) = 19.899\,ft

\bar v = \frac{19.899\,ft-20\,ft}{0.01\,s}

\bar v = -10.1\,\frac{ft}{s}

h = 0.001\,s

y(2) = 30\cdot (2) - 10\cdot (2)^{2}

y (2) = 20\,ft

y(2.001) = 30\cdot (2.001)-10\cdot (2.001)^{2}

y(2.001) = 19.99\,ft

\bar v = \frac{19.99\,ft-20\,ft}{0.001\,s}

\bar v = -10\,\frac{ft}{s}

b) The instantaneous velocity when t = 2\,s can be obtained by using the following limit:

v(t) = \lim_{h \to 0} \frac{x(t+h)-x(t)}{h}

v(t) =  \lim_{h \to 0} \frac{30\cdot (t+h)-10\cdot (t+h)^{2}-30\cdot t +10\cdot t^{2}}{h}

v(t) =  \lim_{h \to 0} \frac{30\cdot t +30\cdot h -10\cdot (t^{2}+2\cdot t\cdot h +h^{2})-30\cdot t +10\cdot t^{2}}{h}

v(t) =  \lim_{h \to 0} \frac{30\cdot t +30\cdot h-10\cdot t^{2}-20\cdot t \cdot h-10\cdot h^{2}-30\cdot t +10\cdot t^{2}}{h}

v(t) =  \lim_{h \to 0} \frac{30\cdot h-20\cdot t\cdot h-10\cdot h^{2}}{h}

v(t) =  \lim_{h \to 0} 30-20\cdot t-10\cdot h

v(t) = 30\cdot  \lim_{h \to 0} 1 - 20\cdot t \cdot  \lim_{h \to 0} 1 - 10\cdot  \lim_{h \to 0} h

v(t) = 30-20\cdot t

And we finally evaluate the instantaneous velocity at t = 2\,s:

v(2) = 30-20\cdot (2)

v(2) = -10\,\frac{ft}{s}

The instantaneous velocity of the ball when t = 2\,s is -10 feet per second.

8 0
3 years ago
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