1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Dvinal [7]
3 years ago
7

42x^2 + 32 - 18 =6062

Mathematics
1 answer:
Elenna [48]3 years ago
4 0
Okay, we start with 42x^2 + 32 - 18 = 6062. To solve single-variable equations like this one, we want to isolate the x by moving all of the other numbers to the other side of the equation. We need to first subtract 32 and 18, and that equals 14. Now our problem looks like this, 42x^2 + 14 = 6062. Since 14 is the only other number on the left side, we subtract four from both sides! This gives us 42x^2 + 14 - 14 = 6062 - 14, so 42x^2 = 6062. Now to find x, we want to just have one x on the left side instead of 42, so we divide the equation by 42 to find that 42x^2/42 = 6048/42, so x = 12
You might be interested in
2x+5y=-3<br>3x-y=21<br>help me
arlik [135]
Problem:
Solve
2
x
+
5
y
=
−
3
;
3
x
−
y
=
21
Steps:
I will try to solve your system of equations.
3
x
−
y
=
21
;
2
x
+
5
y
=
−
3
Step: Solve
3
x
−
y
=
21
for y:
3
x
−
y
+
−
3
x
=
21
+
−
3
x
(Add -3x to both sides)
−
y
=
−
3
x
+
21
−
y
−
1
=
−
3
x
+
21
−
1
(Divide both sides by -1)
y
=
3
x
−
21
Step: Substitute
3
x
−
21
for
y
in
2
x
+
5
y
=
−
3
:
2
x
+
5
y
=
−
3
2
x
+
5
(
3
x
−
21
)
=
−
3
17
x
−
105
=
−
3
(Simplify both sides of the equation)
17
x
−
105
+
105
=
−
3
+
105
(Add 105 to both sides)
17
x
=
102
17
x
17
=
102
17
(Divide both sides by 17)
x
=
6
Step: Substitute
6
for
x
in
y
=
3
x
−
21
:
y
=
3
x
−
21
y
=
(
3
)
(
6
)
−
21
y
=
−
3
(Simplify both sides of the equation)
Answer:
y
=
−
3
and
x
=
6

7 0
3 years ago
(X-7)(3x+2) need answer!!
grin007 [14]

Answer: the answer is

=3x^{2}−19x−14  

Step-by-step explanation:  (x−7)(3x+2)

=(x+−7)(3x+2)

=(x)(3x)+(x)(2)+(−7)(3x)+(−7)(2)

=3x2+2x−21x−14

=3x2−19x−14

7 0
3 years ago
Michelle ordered 200 T-shirts to sell at the school carnival. She paid $2.80 per shirt, plus 5% of the total order for shipping.
djyliett [7]

Answer: She should sell each T-Shirt for at least $4.41

Step-by-step explanation:

First you need to figure out what the total cost of the 200 t shirts was plus shipping. so 200 t shirts for 2.8 would cost $560 + a 5% shipping fee ($28) = 588 if she wants to markup by 150. you would then multiply 588 * 1.5 = $882. This would be the final money she wants to make by the end of her school carnival. Divide 882/200 (amnt of t-shirts) to get $4.41 per shirt

4 0
2 years ago
What is the answer to this o.428​
Anettt [7]

Answer:

0.428o

Step-by-step explanation:

hope this helps

3 0
2 years ago
Instructions: Find the angle measures given the figure is a rhombus.<br> Please Help!
nataly862011 [7]

Answer:

30

Step-by-step explanation:

since this is rhombus 1 2 3 4 must be equal

|NP|=|MN|

so 180-120=60

60/2=30

7 0
2 years ago
Read 2 more answers
Other questions:
  • Suppose that you are provided with the following data for your country for a particular month: 200 million people are working, 2
    9·1 answer
  • The expression 9+219+21 factored using the GCF is
    6·1 answer
  • Solve the inequality.<br><br> 14c&lt;8
    9·1 answer
  • PLS HELP!!!!! A parallelogram is shown below: A parallelogram ABCD is shown with DC equal to 9 feet and the perpendicular distan
    11·1 answer
  • Geometry math question
    12·2 answers
  • E bisects DF, DE = 2y, and EF = 8y - 3. Find DE, EF, and DF. I feel like its easy but for some reason im lost on it, geometry ne
    13·1 answer
  • Perform the indicated operation and write the result in the form a + bi i^100
    13·1 answer
  • How many pieces are there on the rubix cube
    6·2 answers
  • Can any one help me in this please any math genius
    5·1 answer
  • Given the following exponential function, identify whether the change represents
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!