Question

PLEASE HELP ILL GIVE BRAINLIEST!!List the sides of ∆DEF in order from shortest to longest if m∠D = 20, m∠E = 120, and m∠F = 40.

Answer 1

Answer:

In triangle DEF:

Given:  $m\angle D = 20^{\circ}$ ,  $m\angle E= 120^{\circ}$ and  $m\angle F = 40^{\circ}$

To list the sides of a triangle in order from shortest to longest.

In the Figure as shown below :

If one of the angle of a triangle is larger than, then the sides opposite the larger angle is longer than the side opposite to the shorter

$m\angle D < m\angle F < \angle E$

$\text{EF} < \text{DE}$

Therefore, the list of the sides of a triangle DEF in order from shortest to longest is, $\text{EF} < \text{DE}$

Answer 2

Answer:

From shortest to longest:

EF, DE and DF.

Step-by-step explanation:

We know that m∠D = 20, m∠E = 120, and m∠F = 40.

Knowing this measures we can order the sides from shortest to longest, because angles are the opening between to sides, this means if the angle is wide, its opposite side (which is in front of the angle) is wide too, if the angle is narrow, its opposite side will be narrow.

So, in this case, the opposite side of ∠E will be the longest, because this is the largest angle. The opposite side of m∠F will be the second longest, and the opposite side of ∠D will be the smallest. From shortest to longest the order is: EF, DE and DF.

The image attached show this result.