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Minchanka [31]
3 years ago
10

Please help me! Thank you! I only need help with a)

Mathematics
1 answer:
Rzqust [24]3 years ago
8 0

Since we know AD, CD and angle D, we can use the law of cosines, which states that

AC^2 = AD^2+CD^2 - 2AD\cdot CD\cos(D)

Plugging the values, we have

AC^2 = 17^2+13^2 - 2\cdot 17\cdot 13\cos(42)

Which leads to

AC^2 = 458 - 442\cos(42) \approx 129.530

Taking the square root, we have

AC \approx \sqrt{129.530} \approx 11.3811

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50 POINTS:A chess competition has eliminations each round. The table below shows the number of players in each of the first 5 ro
Ket [755]
<span>Round    (x) 1      2     3    4   5 
Players f(x) 256  128  64  32  16

16-256 / 5 - 1 = -240/4 = -60

</span><span>A.) −60; on average, there was a loss of 60 each round. </span>
7 0
3 years ago
Can someone help me on number 8. I tried to do it, but I can’t seem to find the right answer.
qaws [65]

Check the picture below.

4 0
3 years ago
I need help plz and thank u sm
Alchen [17]

Answer:

5x + 3

Step-by-step explanation:

Since we can see DC is the median of Triangle ABC

So it breaks the into two equal parts

Given

AD = 2x + 5

BD = 3x - 2

Now

AB = AB + BD

= 2x + 5 + 3x - 2

= 5x + 3

Hope it will help :)❤

7 0
3 years ago
Please help me I don’t understand this at all and I need to pass quits so please somebody out there help me
kvv77 [185]

Answer:

B) Undefined

Step-by-step explanation:

Vertical lines do not have a horizontal change; the line goes straight up and down. In other words, the change in the x values between any points on the graph is always 0, which would make the denominator of the slope 0. Since anything divided by 0 is undefined, the slope of a vertical line is <u>undefined</u>.

Source: https://www.brightstorm.com/math/algebra/linear-equations-and-their-graphs/finding-the-slope-of-a-line-from-a-graph-problem-3/

7 0
3 years ago
onsider the following problem: A box with an open top is to be constructed from a square piece of cardboard, 3 ft wide, by cutti
Sholpan [36]

Answer:

V (max)  = 2 ft³

and x side of the base is  x  =  0,5 feet

Step-by-step explanation:  See annex ( two different cubes)

We have a square piece of cardboard of  3 inches wide

Let  x be lenght of side to cut in each corner

Then the base of the (future cube) is    3  -  2x,  and the area is  

( 3 - 2x )²

And  the height   is x  Then volume of the cube as a function of x is:

V(x)  =  ( 3 - 2x )² *x   or       V(x)  =    ( 9 + 4x² - 12x )*x

V(x)  =  4x³  -  12x²  + 9x

Taking derivatives on both sides of the equation

V´(x)  =  12x² - 24x  + 9

V´(x)  =  0       12x² - 24x  + 9  =  0   simplifying   4x² - 8x  + 3  =  0

Second degree equation solving for x

x₁,₂ =  [ 24 ± √( 576) - 432  /24

x₁,₂ =  [24 ±√144 ]/24

x₁,₂ = ( 24 ± 12) /24         x₁  =  1.5 feet        x₂  = 0,5 feet

Of these two values we have to dismiss x₁  because if  x = 1.5 we don´t have a cube ( 0 height )

Then we take x  = 0,5  feet

And

V (max)  =  (2)²*0,5   =  4*0,5

V (max)  = 2 ft³

5 0
4 years ago
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