Answer:-4
Step-by-step explanation:
-1 +-4 is -5 and 6/7 + 1/7 =1 so -5 +1=-4
Area = (14 x 20) - ( 5 x 9)
Area = 280 - 45
Area = 235 square cm
Answer is the first choice -5π/2
Answer: the second one
Step-by-step explanation:
Answer:
![Distance = 39.2](https://tex.z-dn.net/?f=Distance%20%3D%2039.2)
Step-by-step explanation:
Given
![Distance = 6ft;\\ Time = 15seconds](https://tex.z-dn.net/?f=Distance%20%3D%206ft%3B%5C%5C%20Time%20%3D%2015seconds)
Required
Determine the distance covered in 98 seconds
To solve this, the following assumption must be made:
- <em>The peacock walks at a constant speed</em>
So, first we calculate the speed
![Speed = \frac{Distance}{Time}](https://tex.z-dn.net/?f=Speed%20%3D%20%5Cfrac%7BDistance%7D%7BTime%7D)
Substitute 6 for Distance and 15 for Time
![Speed = \frac{6}{15}](https://tex.z-dn.net/?f=Speed%20%3D%20%5Cfrac%7B6%7D%7B15%7D)
![Speed = 0.40](https://tex.z-dn.net/?f=Speed%20%3D%200.40)
Next, is to calculate the required distance
![Speed = \frac{Distance}{Time}](https://tex.z-dn.net/?f=Speed%20%3D%20%5Cfrac%7BDistance%7D%7BTime%7D)
In this case:
because it is constant and
![Time = 98](https://tex.z-dn.net/?f=Time%20%3D%2098)
The expression becomes:
![0.40 = \frac{Distance}{98}](https://tex.z-dn.net/?f=0.40%20%3D%20%5Cfrac%7BDistance%7D%7B98%7D)
Make Distance the subject:
![Distance = 0.40 * 98](https://tex.z-dn.net/?f=Distance%20%3D%200.40%20%2A%2098)
![Distance = 39.2](https://tex.z-dn.net/?f=Distance%20%3D%2039.2)
<em>The peacock will walk 39.2 feet in 98 seconds</em>