Question

Find the coordinates of a point that divides a line segment AB in the ratio 2:6.

Answer 1

Answer:

Step-by-step explanation:

The first thing we should do is to calculate the distance AB

To do that we must khow the coordinates of the vector AB

• Vector AB(6-(-6)),-7-9)⇒ Vector AB (12, -16)
• So the distance AB =$\sqrt{12^{2}+(-16)^{2} }$= 20
• now 20 to the ratio of 2:6
• add 2 and 6 2+6=8
• divide 20 by 8  20/8=2.5
• multiplay 2.5 by 2 and 6  2.5*2=5 and 2.5*6= 15
• so the point (3, -3) can satisfy this ration
• if we calculate the remaining distance we find 5 and 15