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babymother [125]

4 years ago

10

The resistances of two bulbs are in ratio 2:3 .The bulbs are connected in series across a battery. Find the ratio of powers in t

he bulbs.

1 answer:

Deffense [45]4 years ago

3 0

$\sf \huge \red{Answer : - }$

Ratio of resistances of two bulbs = 2:3

Both are connected in series.

We have to find the ratio of powers in the bulbs..

We know that, current flow through each conductor in series connection remains same. So, we have to use that formula of power which shows relation between current and resistance.

P = I² × R

For series connection; P ∝ R

→ P₁/P₂ = R₁/R₂

→ P₁/P₂ = 2/3

→ P₁ : P₂ = 2 : 3

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Here is the energy that is left after the quantity of energy is transformed: 750 j of electrical energy is changed into 400 j of kinetic or mechanical energy, which is then turned into 0.32 j of efficient energy.

To run the fan, electrical energy is utilized.

Here, under the specified circumstances, 750 J of electrical energy is utilized to operate the fan, which is transformed into 400 J of kinetic energy. As a result, 350 J of energy is wasted due to various frictional and resistive losses.

Therefore, we may conclude that only 400 J of the 750 J available energy is used to power the fan, with the remaining energy being wasted as a result of friction.

Additionally, we can state that this fan's effectiveness will be

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1 year ago

what is the acceleration of a softball if it has a mass of 0.50kg and hits the catcher’s glove with a force of 25 N

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Answer:

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3 years ago

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3 years ago

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Fofino [41]

The distance between Mars and the Sun in the scale model would be 1140 m

Explanation:

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$d_2=228\cdot 10^6 km$

On the scale model, this would corresponds to a distance of $x_2$ .

Therefore, we can write the following proportion:

$\frac{x_1}{d_1}=\frac{x_2}{d_2}$

And solving for $x_2$ , we find:

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3 years ago

2. a) A disc rotates about its axis at speed 25 revolutions per minute and takes 15 s to stop. Calculate the

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The statement shows a case of rotational motion, in which the disc <em>decelerates</em> at <em>constant</em> rate.

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$\alpha = \frac{\omega_{f}-\omega_{o}}{t}$ (1)

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$\omega_{o}$ - Initial angular speed, in revolutions per second.
$\omega_{f}$ - Final angular speed, in revolutions per second.
$t$ - Time, in seconds.

If we know that $\omega_{o} = \frac{5}{12}\,\frac{rev}{s}$ , $\omega_{f} = 0\,\frac{rev}{s}$ y $t = 15\,s$ , then the angular acceleration of the disc is:

$\alpha = \frac{0\,\frac{rev}{s}-\frac{5}{12}\,\frac{rev}{s}}{15\,s}$

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The angular acceleration of the disc is $\frac{1}{36}$ radians per square second.

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$\Delta \theta = \frac{\omega_{f}^{2}-\omega_{o}^{2}}{2\cdot \alpha}$ (2)

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The disc makes 3.125 revolutions before it stops.

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