Ask question

Ask question

All categories

Mandarinka [93]

4 years ago

14

A 0.66-kg block is hung from and stretches a spring that is attached to the ceiling. A second block is attached to the first one

, and the amount that the spring stretches from its unstrained length increases by a factor of 7. What is the mass of the second block?

1 answer:

Shalnov [3]4 years ago

7 0

Answer:

So the mass of second block will be 3.96 kg

Explanation:

We have given mass of the block m = 0.66 kg

The spring is stanched by the factor 7

From hook's law we know that mg = kx

So $k=\frac{mg}{x}$

Let the mass of second block is M

So $(M+m)g=k(7x)$

Putting the value of m = 0.66 and $k=\frac{mg}{x}$

$(M+0.66)g=\frac{mg}{x}(7x)$

$(M+0.66)=7m$

$(M+0.66)=7\times 0.66=4.62$

$M=3.96kg$

So the mass of second block will be 3.96 kg

You might be interested in

_________ is a change in the position of a body with respect to time relative to a reference point.

rjkz [21]

Answer:

Rest

Explanation:

Rest is a change in the position of a body with respect to time relative to a reference point. The stationary state of an object or body relative to a reference position or another object is called Rest.

Taking Newton's First Law of motion into consideration, an object will remain in its state of rest or uniform motion until acted upon by an external force. This implies an object at rest is an object with zero (without) velocity and acceleration.

8 0

3 years ago

Read 2 more answers

A 30-m-long rocket train car is traveling from Los Angeles to New York at 0.5c when a light at the center of the car flashes. Wh

Novosadov [1.4K]

Given that,

Distance =30 m

speed = 0.5c

(A). We need to find the bell and siren simultaneous events for a passenger seated in the car

According to given data

The distance travelled by the light to reach either side of the rocket train car is same.

So, The two events are simultaneous and the bell and siren are the simultaneous events for a passenger seated in the car.

(B). We need to calculate time interval between the events

Using formula of time dilation

$\Delta t=\dfrac{\Delta t'}{\sqrt{1-\dfrac{v^2}{c^2}}}$ .....(I)

Where, $\delta t'$ = proper time

$\delta t$ = time interval between the events

The time interval between the events measured in a reference frame

The proper time in this case is

$\Delta t'=\Delta t_{1}-\dfrac{v\Delta x}{c^2}$

For the second interval,

Put the value of $\Delta t'$ in the equation (I)

$\Delta t_{2}=\dfrac{\Delta t_{1}-\dfrac{v\Delta x}{c^2}}{\sqrt{1-\dfrac{v^2}{c^2}}}$

Put the value in the equation

$\Delta t_{2} = \dfrac{0-\dfrac{0.5c\times30}{c^2}}{\sqrt{1-\dfrac{0.5^2c^2}{c^2}}}$

$\Delta t_{2}=\dfrac{-15}{3\times10^{8}\sqrt{1-0.25}}$

$\Delta t_{2}=-5.77\times10^{8}\ s$

Negative sign shows the siren rings before the bell ring.

Hence, (A). Yes, the bell and siren are simultaneous events.

(B). The siren sounds before the bell rings.

8 0

3 years ago

A 1500-kg car locks its brakes and skids to a stop on a slippery horizontal road, leaving skid marks that are 15 m long. How muc

Harman [31]

Answer:

$E=88200\ J$

Explanation:

Given:

mass of car, $m=1500\ kg$

distance of skidding after the application of brakes, $d=15\ m$

coefficient of kinetic friction, $\mu_k=0.4$

<u>So, the energy dissipated during the skidding of car:</u>

<em>Frictional force:</em>

$f=\mu_k.N$

where N = normal reaction by ground on the car

$f=0.4\ties 1500\times 9.8$

$f=5880\ N$

<em>Now from the work-energy equivalence:</em>

$E=f.d$

$E=5880\times 15$

$E=88200\ J$ is the dissipated energy.

3 0

3 years ago

A bowling ball of mass 5.8 kg moves in a

evablogger [386]

Answer:

Velocity of the ping pong ball must be = V2= 6,035.34m/s

Explanation:

M1= momentum of the bowling ball

m1 = mass of the bowling ball= 5.8kg

v1= velocity of the bowling ball= 1.59m/s

M2= momentum of the ping pong ball

m2= mass of the ping pong ball= 1.528 g/1000= 0.001528kg

v2= velocity of the ping pong ball

Momentum of the bowling ball= M1= m1v1= 5.8* 1.59= 9.222 kg-m/s

Momentum of the ping pong ball = M2= M1= m2v2

= 0.001528 *v2= 9.222

v2= 9.222/0.001528= 6,035.34 m/s

7 0

4 years ago

PLEASE HELP!!! WILL GET BRAINIEST FOR 5 SENTENCES

emmasim [6.3K]

Hello.

BEVs and hydrogen fuel cell vehicles are a more promising transportation technology for the future because they reduce greenhouse gas emissions as well as CO2 making it more 'green.' The second question is your opinion, in mine no, they should not be required but they should at least be considering.
Have a nice day

5 0

3 years ago