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4 years ago

Find the value of k if the graph of the equation y=kx−4 passes through the point A(−2,6).

Mathematics

1 answer:

neonofarm [45]4 years ago

5 0

$y = kx - 4$

$x = - 2 \\ y = 6$

$6 = k( - 2) - 4 \\ 6 + 4 = - 2k \\ 10 = - 2k \\ k = \frac{10}{ - 2} \\ k = - 5$

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Answer choices are 14 24 28 48

MrRa [10]

Answer: 24 square units

Step-by-step explanation:

It appears the shaded area of the rectangle is half of the rectangle's area. This means if we find the area of the rectangle and divide it by 2 we will know the area of the shaded portion.

The formula for the area of a rectangle is $lw=A$

Where

l is the length (8 for this)

w is the width (6 for this)

A is the area

However, since we are finding half the area we will divide lw by 2

Sub the values into the formula

$\frac{lw}{2} =A\\\frac{(8)(6)}{2} =A\\\frac{48}{2} =A\\24=A$

4 0

2 years ago

Help please ASAP 3:28 pm est answer as soon as you can!

Anna007 [38]

Answer:

where is the answer at

Step-by-step explanation:

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3 years ago

If 3m - n = 11, then m =

irina [24]

Answer:

n= -2 and m=3

Step-by-step explanation:

3 x 3= 9

11- 9 = 2

5 0

3 years ago

PLEASE HELP IM BEGGING! U WILL EARN 85 POINTS - WILL MARK BRAINLIEST

dimulka [17.4K]

Answer:

See below

Step-by-step explanation:

The graph is attached

|2x - 4| = mx + 1

It has only one solution when the line mx + 1 is parallel to one part of |2x - 4|.

As per graph, we see m = 2 makes it parallel to y = 2x - 4. This is the only solution.

---------------------------

Now, as I understand, you are looking for 2 solutions instead of one. It means the line mx + 1 will have 2 points of intersection with the line |2x - 4|.

One of those solutions is attached as well, where m = 1. And you may get many more options for this.

4 0

3 years ago

Show me how you solve it

julia-pushkina [17]

Answer:

5^20

Step-by-step explanation:

Law of Exponent I

$\displaystyle \large{ \frac{ {a}^{m} }{ {a}^{n} } = {a}^{m - n} }$

Therefore:

$\displaystyle \large{( \frac{ {5}^{8} }{ {5}^{3} } )^{4} = ({5}^{8 - 3})^{4} } \\ \displaystyle \large{( \frac{ {5}^{8} }{ {5}^{3} } )^{4} = ({5}^{5})^{4} }$

Law of Exponent II

$\displaystyle \large{( {a}^{m} ) ^{n} = {a}^{m \times n} }$

Thus:

$\displaystyle \large{( \frac{ {5}^{8} }{ {5}^{3} } )^{4} = ({5}^{8 - 3})^{4} } \\ \displaystyle \large{( \frac{ {5}^{8} }{ {5}^{3} } )^{4} = ({5}^{5})^{4} } \\ \displaystyle \large{( \frac{ {5}^{8} }{ {5}^{3} } )^{4} = {5}^{5 \times 4} } \\ \displaystyle \large{( \frac{ {5}^{8} }{ {5}^{3} } )^{4} = {5}^{20} }$

7 0

3 years ago