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Liono4ka [1.6K]
3 years ago
12

PLS ANS THIS QUESTION WILL DECLARE BRAINLEST..

Chemistry
1 answer:
LuckyWell [14K]3 years ago
6 0
Carbon Dioxide (CO2) .
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The combustion of acetylene gas is represented by this equation: 2C2H2(g) + 5O2(g) → 4CO2(g) + 2H2O(g)
MAVERICK [17]

Answer:

Approximately 2.46\; \rm mol.

Explanation:

Make use of the molar mass data (M({\rm C_2H_2}) = 26.04\; \rm g \cdot mol^{-1}) to calculate the number of moles of molecules in that 64.0\; \rm g of \rm C_2H_2:

\begin{aligned}n({\rm C_2H_2}) &= \frac{m({\rm C_2H_2})}{M} \\ &= \frac{64.0\; \rm g}{26.04\; \rm g\cdot mol^{-1}}\approx 2.46\; \rm mol\end{aligned}.

Make sure that the equation for this reaction is balanced.

Coefficient of \rm C_2H_2 in this equation: 2.

Coefficient of \rm H_2O in this equation: 2.

In other words, for every two moles of \rm C_2H_2 that this reaction consumes, two moles of \rm H_2O would be produced.

Equivalently, for every mole of \rm C_2H_2 that this reaction consumes, one mole of \rm H_2O would be produced.

Hence the ratio: \displaystyle \frac{n({\rm H_2O})}{n({\rm C_2H_2})} = \frac{2}{2} = 1.

Apply this ratio to find the number of moles of \rm H_2O that this reaction would have produced:

\begin{aligned}n({\rm H_2O}) &= n({\rm C_2H_2}) \cdot \frac{n({\rm H_2O})}{n({\rm C_2H_2})} \\ &\approx 2.46\; \rm mol \times 1 = 2.46\; \rm mol\end{aligned}.

3 0
3 years ago
What does AuCl, Gold (I) Chloride, decompose into?
Alexxx [7]

Answer:

Gold

Explanation:

Gold(I) chloride is a compound of gold and chlorine with the chemical formula AuCl

6 0
3 years ago
Pennies are made of zinc coated with copper. Copper has a work function of 4.7 eV. The ozone layer blocks nearly all solar radia
Vadim26 [7]

Answer:

yes  it can  λ =265  nm

Explanation:

Here we will use  the relationship

   E = h c/λ  ∴   λ  = E/ hc  where

                                          h= Plank's constant

                                           c= Speed of light

                                           λ = Wavelength = ?

Substituting

note need E in J ,

E = 4.7 eV x 1.602 x 10⁻¹⁹ J/eV = 7.5 x 10⁻¹⁹ J)

λ = 7.5 x 10 ⁻¹⁹ J / (  6.626 x 10⁻³⁴ Js x 3 x 10^8) =  2.65 x 10⁻⁷ m = 2.65

=  2.65 x 10⁻⁷ m x 1 x 10⁹ nm/m = 265 nm

4 0
3 years ago
Help please stuck and confused
Alecsey [184]
I’m pretty sure it’s none of the above cause I’m googling it a bunch and and it say you use the dideoxy method
7 0
3 years ago
Sakura tested the ph of several solutions. which substances are acidic? check all that apply. cola-flavored soda: 2.6 cranberry
Step2247 [10]

Answer:- Cola-flavored soda:2.6, cranberry juice:2.9 and pickle juice:5.5 are acidic.

Explanations:- As per the pH scale, the solution is acidic if the pH is below 7 and the solution is basic if the pH is above 7. The solution is neutral if the pH is exactly 7.

There are only three solutions with pH value below 7 and so they are acidic. these three solutions are, cola-flavored soda, cranberry juice and pickle juice.

Rest of them are basic as their pH value is greater than 7.

5 0
4 years ago
Read 2 more answers
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